Special Relativity Question John carries a meter stick and runs through a barn door that is 1 meter wide. Sally observes from inside the barn. Why CANNOT the meter stick space contract if John holds it perpendicular to his motion?
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John carries a meter stick and runs through a barn door that is 1 meter wide. Sally observes from inside the barn. Why CANNOT the meter stick space contract if John holds it perpendicular to his motion?
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- Special relativity lorentz Due to the rotation of the earth the speed of a point in the equator is 460 m/s with respect to a point in the north pole. According to the effect of time dilation in relativity, why do the clock rhythms differ if one is in the equator and the other at the north pole? after a year, for how many seconds do the clocks differ?1) A 5-kg particle's momentum is (211, 329) kg*m/s. Calculate its kinetic energy. 2)Calculate the x-component of vSJ. vS = 6 km/s vJ = 9 km/s θ = 23o 3) In Jupiter's frame, the incoming spacecraft is moving rightward and upward, at 45o. The outgoing spacecraft, having already flown by, is going at the same relative speed, but leftward and upward, also at 45o. (See the figures.) You are going to transform back to the sun's frame and calculate the final outgoing speed. You need to follow several steps: Calculate the vector components of the outgoing vSJ. Add Jupiter's vector velocity to get the outgoing vS. Finally calculate the outgoing speed, vS = |vS| in km/s. Enter that as the final answer. use these parameters: vSJ = 4 km/s vJ = 8 km/smultiple choice question As the velocity of an inertial frame of reference increases with respect to a stationary observer, Einstein's theory of special relativity predicts that the length of an object, measured in the dimension parallel to the motion of the reference frame, will A decrease. B. remain unchanged. Jump to 1 2 3 4 5 6 7 8 9 10 increase. D. increase at first but start to decrease when the speed of the reference frame equals half the speed of light. E. decrease at first but start to increase when the speed of the reference frame equals half the speed of light.
- 4. Bob is moving away from Alice with speed of 0.5c. Carlos is moving away from Alice and to Bob with speed of 0.8c. What is the speed of Carlos as measured by perpendicular Bob?Please please please answer everything super super fast please5. A stationary observer fires a laser. An observer in a space ship is moving to the left at 0.99c. What is the magnitude of the speed of light as measured by the observer in the ship ? Just don't state that it is c. Show that it is e
- 9. An astronomer on earth observes two spacecraft moving away from each other along an axis that passes through the earth. The astronomer measures the speed of each spacecraft to be 0.875c relative to the earth. At what speed are the spacecrafts moving apart relative to each other? a) 0.496c b) 0.467c c) 1.750c d) 0.143c e) 0.991c 10. How far apart must two objects on the moon be to be resolved by a telescope which has a 7.80-m diameter mirror? The wavelength of the light used is A610 nm, and the distance to the moon to be 3.80 x 105 km. a) 24.4 m b) 29.7 m c) 36.3 m d) 72.5 m e) 12.2 m 11. A converging lens with a focal length of (f₁ = 32.0 cm) is placed 42.0 cm to the left of a diverging lens with a focal length of (f2 = -25.5 cm). An object is placed 40.0 cm to the left of the converging lens. What is the location of the image produced by the combination of lenses? a) 32.5 cm to the right of the diverging lens b) 32.5 cm to the left of the diverging lens c) 160 cm to the left of the…You are in a spaceship with no windows, radios, or other means to check outside. How would you determine if the spaceship is at rest or moving at constant velocity? a) By determining the apparent velocity of light in the spaceship b) By checking your precision watch. If it's running slow, then the ship is moving. c) By measuring the lengths of objects. in the spaceship. If they are shorter, then the ship is moving. d) By measuring your weight on a scale located in the spaceship. If you have gained mass, then the ship is moving. e) You should give up because you've taken on a impossible task.Example 6 Bob, who is stationary, measures the length of a moving relativistic train and finds out 50 m. The train passes through a tunnel of length 25 m at a speed 0.5c. Place on a space-time (Minkowski) diagram the following events: (a) Event A: the front of train at the exit of the tunnel. (b) Event B: the front of the train at the entrance of the tunnel. (c) Event C: the rear of the train at the exit of the tunnel. (d) Event D: the rear of the train at the entrance of the tunnel.