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Span Span = Span ((1, 2, 2), (0, 1, 1)), P2 = Span -= Span ((1,0, –1), (1, 2, 3)), P2 = {x = Span (1, 1, 0, 1), (0, 1, 1, 0)), P2 =: = Span ((1,0, 1, 2), (0, 1, 0, –1)), P2 = %3D

Span Span = Span ((1, 2, 2), (0, 1, 1)), P2 = Span -= Span ((1,0, –1), (1, 2, 3)), P2 = {x = Span (1, 1, 0, 1), (0, 1, 1, 0)), P2 =: = Span ((1,0, 1, 2), (0, 1, 0, –1)), P2 = %3D

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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linear algebra 3.1 Q9 only sub question b

9. Determine the intersection of the subspaces P1 and P2 in each case: *а. Pi %3D Span ((1, 0, 1), (2, 1, 2)), Р2 %3D Span (1, —1, 0), (1, 3, 2)) b. P1 %3D 3 с. Р 3DSpan ( — х2 + хз 3D 0} Span ((1, 2, 2), (0, 1, 1)), P2 Span ((2, 1, 1), (1, 0, 0) 6. (1, 0, —1), (1, 2, 3)), P2 — (х: Х1 *d. P1 = = Span ((0, 0, 1, 1), (1, 1, 0, 0)) Span ((1, 1, 0, 1), (0, 1, 1, 0)), P2 Р, %3D Span ((1,0, 1, 2), (0, 1, 0, —1), , %3D Span ((1, 1, 2, 1), (1, 1, 0, 1))
Transcribed Image Text:9. Determine the intersection of the subspaces P1 and P2 in each case: *а. Pi %3D Span ((1, 0, 1), (2, 1, 2)), Р2 %3D Span (1, —1, 0), (1, 3, 2)) b. P1 %3D 3 с. Р 3DSpan ( — х2 + хз 3D 0} Span ((1, 2, 2), (0, 1, 1)), P2 Span ((2, 1, 1), (1, 0, 0) 6. (1, 0, —1), (1, 2, 3)), P2 — (х: Х1 *d. P1 = = Span ((0, 0, 1, 1), (1, 1, 0, 0)) Span ((1, 1, 0, 1), (0, 1, 1, 0)), P2 Р, %3D Span ((1,0, 1, 2), (0, 1, 0, —1), , %3D Span ((1, 1, 2, 1), (1, 1, 0, 1))
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