spanof Gm.3. Using the RULE OF THUMB", find theinitial size of the beam with a simple4.5mR1R2span of 4.5 m.Conct HW#3 4. Design a monolithic reinforced concrete7.5mslab having cleardimensions ofspan6m x 7.5 m. The floor slab is to carryFLOORSLAB6ma service live load of GKPA uniformlydistributed over its surface. Use fc'= 28 MAuand fy = 415 MPa.

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Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A 400 * 300 mm rectangular column is reinforced with four No.36 bars, one in each corner, with cover distances 65 mm to the steel center in each direction Material strengths are f_{c}' = 35 MPa and f_{y} = 420MPa Construct the interaction diagram relating axial strength P_{n} and flexural strength M_{n} Bending will be about an axis parallel to one face Calculate the coordinates for P_{0} P_{b} and at least two other representative points on the curve.
Assignment 5.1 -Steel Beam Analysis -600 lb/ft e-1,200 lb/ft W 10 x 88 A992 Steel The beam carries the following service dead load and live load 10 10 10 = 600 lb/ft - 1,200 lb/ft 30h Check to see whether the Lateral support is provided at both ends and at the one-third points given section can safely carry the applied loads
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The wood beam supports loads of w = 430 lb/ft and P = 900 Ib on span lengths of LAB = 10.4 ft, Lgc = 5.2 ft, and Lco= 5.2 ft. The beam cross section has dimensions of b, = 1.3 in., dz = 3.9 in., b2 = 5.3 in., and d2 = 11.45 in. Determine the magnitude and location of: (a) the maximum horizontal shear stress in the beam. (b) the maximum tensile bending stress in the beam. P di d2 B LAB Lục LBC LCD b b2 Answer: (а) Тmax psi (b) Omax psi
A 572 Grade 65 steel with Fy = 448 MPa is used as a simple beam to carry a concentrated load P at the center of its span on a 6m simply supported span. The beam is W 12 x 14 section having the given properties shown. Properties of W 12 x 14 Weight of beam = 204.76 N/m Area = 2658 mm2 Depth (d) = 302.514 mm Flange Width (bf) = 100.787 mm Flange Thickness (tf) = 5.690 mm Web Thickness (tw) = 5.029 mm Section Modulus = 242 529 mm3
Work out the quantity of steel in a 5m long simply supported beam of size 150 X 400mm overall. Bottom bar: 4- 10mm diameter straight bars. Anchor bar: 2-08mm diameter straight bars, stirrups 8min diameter @ 150mm cic throughout the length of the beam. Clear cover as 10mm on all sides.
Please answer the situation 1 only
From load analysis, the following are the factored design forces result: Mu = 440 KN-m, Vu = 280 KN. The beam has a width of 400 mm and a total depth of 500 mm. Use f’c = 20.7 MPa, fy for main bars is 415 MPa, concrete cover to the centroid of the bars both in tension and compression is 65 mm, steel ratio at balanced condition is 0.02, lateral ties are 12 mm diameter. Normal weight concrete. Calculate the required area of compression reinforcement in mm2 due to the factored moment, Mu. Express your answer in two decimal places.
please answer situation 3 only
Steel Design W21x62 steel is used as a beam simply supported over a span of 8 m. The beam is laterally unsupported over the entire span Fy = 250 MPa. The properties of the section are as follows: Depth, d = 533 mm Flange width, bf = 210 mm Flange thickness, tf = 15.6 mm Web thickness, tw = 10.2 mm Radius of gyration, rT = 53.34 mm Section modulus, Sx = 2,077 x 103 mm³ a) Determine the value of the ratio L/rT. b) Determine the allowable bending stress in MPa.
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span of Gm. 3. Using the * RULE OF THUMB" find the initial size of the beam with a simple 4.5m RI R2 span of 4.5 m.