Space is considered a perfect black body with T= - 70 celsius Air Does not absorb heat radiation from the water in the bowl. Air temperature is considered constant TAir = 15 celsius Heat transfer coefficient from water to air: hc = 2.6 W/(m2∙celsius) cabbage with water Depth to the water in the bowl: H = 0.020 m Base area to water layer: A= 0.020 m2 Starting temperature: T0 = 15 celsius Emissivity to water:  = 0.98  a) Calculate heat transport by radiation from the water in the bowl to space at initial conditions.   b) Calculate net heat transport from the water in the bowl at water temperature T= 0 celsius (beginning of freezing).

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
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ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
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Chapter11: Heat Transfer By Radiation
Section: Chapter Questions
Problem 11.66P
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Space is considered a perfect black body with T= - 70 celsius

Air
Does not absorb heat radiation from the water in the bowl.
Air temperature is considered constant TAir = 15 celsius
Heat transfer coefficient from water to air: hc = 2.6 W/(m2∙celsius)

cabbage with water
Depth to the water in the bowl: H = 0.020 m
Base area to water layer: A= 0.020 m2
Starting temperature: T0 = 15 celsius
Emissivity to water:  = 0.98 

a) Calculate heat transport by radiation from the water in the bowl to space at initial conditions.
 
b) Calculate net heat transport from the water in the bowl at water temperature T= 0 celsius (beginning of freezing).

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