Source and Color of Line 1. H (red) n = 3→n=2 2. H (blue) n=4 →n=2 3. H (violet) n = 5→n=2 . He (yellow) -.Hg (green) - Η n=2 →n=1 a (cm) 100 d Wavelength Wavelength Frequ (cm) (cm) (nm) (s -8 0.3867 1.06x10 1166167 30 0.287 3 7.95-169 b (cm) 42, 77897 26 0.254 6.9875 (6980 38.9 34. 0.3709 6.03 X1075 0.3277 5.35.105 535 603 0 535 10 Show calculation to determine d here:
Source and Color of Line 1. H (red) n = 3→n=2 2. H (blue) n=4 →n=2 3. H (violet) n = 5→n=2 . He (yellow) -.Hg (green) - Η n=2 →n=1 a (cm) 100 d Wavelength Wavelength Frequ (cm) (cm) (nm) (s -8 0.3867 1.06x10 1166167 30 0.287 3 7.95-169 b (cm) 42, 77897 26 0.254 6.9875 (6980 38.9 34. 0.3709 6.03 X1075 0.3277 5.35.105 535 603 0 535 10 Show calculation to determine d here:
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
Fill in the remaining columns except kj/mole

Transcribed Image Text:hemistry M01A Lal
Source and
Color of Line
1. H (red)
n=3 →n=2
2. H (blue)
n=4 →n=2
3. H (violet)
n=5 ⇒n=2
4. He (yellow)
5. Hg (green)
6. H
n=2 →n=1
7. H
n=∞→n=1
8. H
n=4 →n=3
9. H
n=∞→n=3
10. H
n=∞→n=2
a
(cm)
42
100
yall La/ STAD
b
(cm)
d
(cm)
0.3567 1.06x108
30 0.287 3 7.99-109
42,
Energy
Wavelength Wavelength Frequency
(cm)
(nm)
(S-¹) (J/photon) (kJ/mole)
Energy
1166167
7.7897
26
38.9
34.
S
0.254 6.98x6 (698
0.3709 6.03 X10
603
0,3277 5.35.10 535
-5
Show calculation to determine d here:
Rydberg Eq
calculation
of λ (nm)
IR, Vis, UV
IR, Vis, UV
IR, Vis, UV
IR, Vis, UV
IR, Vis, UV
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