Sorry, my fault (√4x+2y)+(√4xy)=10.1289902044924 4x+2y is one square and 4xy is another square root. So here is the question again use implicit differentiation to find dy/dx and then find the slope of the tangent line to the curve below at the point (1,8). (√4x+2y)+(√4xy)=10.1289902044924
Sorry, my fault (√4x+2y)+(√4xy)=10.1289902044924 4x+2y is one square and 4xy is another square root. So here is the question again use implicit differentiation to find dy/dx and then find the slope of the tangent line to the curve below at the point (1,8). (√4x+2y)+(√4xy)=10.1289902044924
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Sorry, my fault (√4x+2y)+(√4xy)=10.1289902044924
4x+2y is one square and 4xy is another square root. So here is the question again use implicit
(√4x+2y)+(√4xy)=10.1289902044924
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