Somewhere you place a 8 kg pumpkin on a spring scale. If the scale reads 64 N, what is the acceleration due to gravity at that location? 09.8 m/s² 08 m/s² 09.8 m/s² 032 m/s²
Somewhere you place a 8 kg pumpkin on a spring scale. If the scale reads 64 N, what is the acceleration due to gravity at that location? 09.8 m/s² 08 m/s² 09.8 m/s² 032 m/s²
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Physics Question: Acceleration Due to Gravity
**Problem Statement:**
Somewhere you place an 8 kg pumpkin on a spring scale. If the scale reads 64 N, what is the acceleration due to gravity at that location?
**Answer Choices:**
- ( ) \(9.8 \, m/s^2\)
- ( ) \(8 \, m/s^2\)
- ( ) \(9.8 \, m/s^2\)
- ( ) \(32 \, m/s^2\)
**Explanation:**
When you place an object on a spring scale, the scale measures the force of gravity on that object, which is also known as the weight. The weight \( W \) of the object is given by the equation:
\[ W = m \cdot g \]
where:
- \( W \) is the weight in Newtons (N),
- \( m \) is the mass in kilograms (kg),
- \( g \) is the acceleration due to gravity in meters per second squared (m/s²).
Given:
- Weight \( W \) = 64 N,
- Mass \( m \) = 8 kg.
Rearranging the formula to solve for \( g \):
\[ g = \frac{W}{m} \]
Substituting the known values:
\[ g = \frac{64 \, \text{N}}{8 \, \text{kg}} = 8 \, m/s^2 \]
Therefore, the acceleration due to gravity at that location is \( 8 \, m/s^2 \).
**Correct Answer:**
- (○) \(8 \, m/s^2\)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1642103c-b9cb-4877-b43c-9c095146cfd7%2Fe7a1abb8-24cc-44e6-9b08-7677870f417f%2Fodd4qvg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Physics Question: Acceleration Due to Gravity
**Problem Statement:**
Somewhere you place an 8 kg pumpkin on a spring scale. If the scale reads 64 N, what is the acceleration due to gravity at that location?
**Answer Choices:**
- ( ) \(9.8 \, m/s^2\)
- ( ) \(8 \, m/s^2\)
- ( ) \(9.8 \, m/s^2\)
- ( ) \(32 \, m/s^2\)
**Explanation:**
When you place an object on a spring scale, the scale measures the force of gravity on that object, which is also known as the weight. The weight \( W \) of the object is given by the equation:
\[ W = m \cdot g \]
where:
- \( W \) is the weight in Newtons (N),
- \( m \) is the mass in kilograms (kg),
- \( g \) is the acceleration due to gravity in meters per second squared (m/s²).
Given:
- Weight \( W \) = 64 N,
- Mass \( m \) = 8 kg.
Rearranging the formula to solve for \( g \):
\[ g = \frac{W}{m} \]
Substituting the known values:
\[ g = \frac{64 \, \text{N}}{8 \, \text{kg}} = 8 \, m/s^2 \]
Therefore, the acceleration due to gravity at that location is \( 8 \, m/s^2 \).
**Correct Answer:**
- (○) \(8 \, m/s^2\)
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