SOMEONE PLEASE I DONT UNDERSTAND THIS HELP ME ANSUR is an abbreviation of anthropometric surveyUse the accompanying sample of weights (kg) of the males from the data set ANSURI 1988 which were measured from U.S. army personnel in 1988 and use the accompanying sample of weights (kg) of the males from the data set ANSUR 2012which were measured from U.S. army personnel in 2012. Use software or a calculator to find the means and medians. Does it appear that males have become heavier?A- The mean of the given ANSUR I 1988 data is kg. (Type an integer or decimal rounded to two decimal places as needed .) B- The mean of the given ANSUR 2012 data is kg. (Type an integer or decimal rounded to two decimal places as needed .) C- The median of the given ANSUR I 1988 data is kg. (Type an integer or decimal rounded to two decimal places as needed .) D- The median of the given ANSUR 2012 data is kg. Type an integer or decimal rounded to two decimal places as needed.)Does it appear that males have become heavier ? (Blank) because the mean (blank) from 1988 to 2012 and the median (blank) from 1988 to 2012. 988 to 2012.APlease copy and paste data from text area below.Selected delimiter: TabvANSUR I 1988106.974.268.290.867.378.470.356.088.770.077.869.574.876.580.362.064.066.485.460.865.581.873.964.589.471.982.256.279.075.075.577.482.897.758.580.066.073.057.276.273.077.187.960.982.599.482.089.0POD82.3944075.874.284.372.383.463.081.3121.281.875.871.389.998.8115.464.467.786.583.585.273.955.675.281.292.492.067.7110.575.482.5121.887.8.86.971.5109.9120.495.279.0112.473.5109.178.9---99.474.8103.62039.953.374.470.977.981.4102.685.887.381.959.7 94.172.9 81.071.970.668.288.4....MAANSUR II 2012Done- X the data set "ANSUR I 1988," which were mD 2012.AJUJU53.374.470.977.981.4102.6 85.8103.082.375.874.284.372.387.359.772.983.463.081.378.965.380.388.588.176.877.164.493.496.579.074.293.372.983.989.664.969.967.365.772.788.980.971.577.585.686.078.874.1HORA77.0HOM79.2Mana81.9PAR100.265.171.478.878 8161.061.076.990.274.981.994.181.071.970.668.288.4104.274.456.688.790.764.978.064.592.077.793.381.887.096.964.685.287.192.080.788.182.268.045.963.380.971.786.6www71.8Ho76.694.2MANA61.374.4MOOT108.086.687.378.076.095.4103.389.186.965.2 90.585.181.9105.3 57.571.170.299.294.7Doneple of weights (kg) of the males from the data set "ANSUR II 2012," wheX-X

Answered: SOMEONE PLEASE I DONT UNDERSTAND THIS…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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SOMEONE PLEASE I DONT UNDERSTAND THIS HELP ME ANSUR is an abbreviation of anthropometric surveyUse the accompanying sample of weights (kg) of the males from the data set ANSURI 1988 which were measured from U.S. army personnel in 1988 and use the accompanying sample of weights (kg) of the males from the data set ANSUR 2012which were measured from U.S. army personnel in 2012. Use software or a calculator to find the means and medians. Does it appear that males have become heavier? A- The mean of the given ANSUR I 1988 data is kg. (Type an integer or decimal rounded to two decimal places as needed .) B- The mean of the given ANSUR 2012 data is kg. (Type an integer or decimal rounded to two decimal places as needed .) C- The median of the given ANSUR I 1988 data is kg. (Type an integer or decimal rounded to two decimal places as needed .) D- The median of the given ANSUR 2012 data is kg. Type an integer or decimal rounded to two decimal places as needed.) Does it appear that males have become heavier ? (Blank) because the mean (blank) from 1988 to 2012 and the median (blank) from 1988 to 2012.

988 to 2012.
A
Please copy and paste data from text area below.
Selected delimiter: Tab
v
ANSUR I 1988
106.9
74.2
68.2
90.8
67.3
78.4
70.3
56.0
88.7
70.0
77.8
69.5
74.8
76.5
80.3
62.0
64.0
66.4
85.4
60.8
65.5
81.8
73.9
64.5
89.4
71.9
82.2
56.2
79.0
75.0
75.5
77.4
82.8
97.7
58.5
80.0
66.0
73.0
57.2
76.2
73.0
77.1
87.9
60.9
82.5
99.4
82.0
89.0
POD
82.3
9440
75.8
74.2
84.3
72.3
83.4
63.0
81.3
121.2
81.8
75.8
71.3
89.9
98.8
115.4
64.4
67.7
86.5
83.5
85.2
73.9
55.6
75.2
81.2
92.4
92.0
67.7
110.5
75.4
82.5
121.8
87.8
.86.9
71.5
109.9
120.4
95.2
79.0
112.4
73.5
109.1
78.9
---
99.4
74.8
103.6
20
39.9
53.3
74.4
70.9
77.9
81.4
102.6
85.8
87.3
81.9
59.7 94.1
72.9 81.0
71.9
70.6
68.2
88.4
....
MA
ANSUR II 2012
Done
- X

the data set "ANSUR I 1988," which were m
D 2012.
A
JUJU
53.3
74.4
70.9
77.9
81.4
102.6 85.8
103.0
82.3
75.8
74.2
84.3
72.3
87.3
59.7
72.9
83.4
63.0
81.3
78.9
65.3
80.3
88.5
88.1
76.8
77.1
64.4
93.4
96.5
79.0
74.2
93.3
72.9
83.9
89.6
64.9
69.9
67.3
65.7
72.7
88.9
80.9
71.5
77.5
85.6
86.0
78.8
74.1
HORA
77.0
HOM
79.2
Mana
81.9
PAR
100.2
65.1
71.4
78.8
78 8
161.0
61.0
76.9
90.2
74.9
81.9
94.1
81.0
71.9
70.6
68.2
88.4
104.2
74.4
56.6
88.7
90.7
64.9
78.0
64.5
92.0
77.7
93.3
81.8
87.0
96.9
64.6
85.2
87.1
92.0
80.7
88.1
82.2
68.0
45.9
63.3
80.9
71.7
86.6
www
71.8
Ho
76.6
94.2
MANA
61.3
74.4
MOOT
108.0
86.6
87.3
78.0
76.0
95.4
103.3
89.1
86.9
65.2 90.5
85.1
81.9
105.3 57.5
71.1
70.2
99.2
94.7
Done
ple of weights (kg) of the males from the data set "ANSUR II 2012," whe
X
-
X

Definition Definition Middle value of a data set. The median divides a data set into two halves, and it also called the 50th percentile. The median is much less affected by outliers and skewed data than the mean. If the number of elements in a dataset is odd, then the middlemost element of the data arranged in ascending or descending order is the median. If the number of elements in the dataset is even, the average of the two central elements of the arranged data is the median of the set. For example, if a dataset has five items—12, 13, 21, 27, 31—the median is the third item in ascending order, or 21. If a dataset has six items—12, 13, 21, 27, 31, 33—the median is the average of the third (21) and fourth (27) items. It is calculated as follows: (21 + 27) / 2 = 24.

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