Someone has suggested that the air-standard Otto cycle is more accurate if the two polytropic processes are replaced with isentropic processes. Consider such a cycle when the compression ratio is 8, P₁ = 95 kPa, T₁= 15°C, and the maximum cycle temperature is 1800°C. Determine the heat transferred to and rejected from this cycle, as well as the cycle's thermal efficiency. Use constant specific heats at room temperature. The properties of air at room temperature are cp=1.005 kJ/kg-K, cy=0.718 kJ/kg-K, R = 0.287 kJ/kg-K, and k=1.4. The heat transferred to this cycle is The heat rejected from this cycle is The thermal efficiency is %. kJ/kg. kJ/kg.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
icon
Related questions
Question
100%
Someone has suggested that the air-standard Otto cycle is more accurate if the two polytropic processes are replaced with isentropic
processes. Consider such a cycle when the compression ratio is 8, P₁ = 95 kPa, T₁ = 15°C, and the maximum cycle temperature is
1800°C. Determine the heat transferred to and rejected from this cycle, as well as the cycle's thermal efficiency. Use constant specific
heats at room temperature. The properties of air at room temperature are cp=1.005 kJ/kg-K, cy= 0.718 kJ/kg-K, R = 0.287 kJ/kg-K,
and k=1.4.
The heat transferred to this cycle is
The heat rejected from this cycle is
The thermal efficiency is
%.
kJ/kg.
kJ/kg.
Transcribed Image Text:Someone has suggested that the air-standard Otto cycle is more accurate if the two polytropic processes are replaced with isentropic processes. Consider such a cycle when the compression ratio is 8, P₁ = 95 kPa, T₁ = 15°C, and the maximum cycle temperature is 1800°C. Determine the heat transferred to and rejected from this cycle, as well as the cycle's thermal efficiency. Use constant specific heats at room temperature. The properties of air at room temperature are cp=1.005 kJ/kg-K, cy= 0.718 kJ/kg-K, R = 0.287 kJ/kg-K, and k=1.4. The heat transferred to this cycle is The heat rejected from this cycle is The thermal efficiency is %. kJ/kg. kJ/kg.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Power Plant Engineering
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Elements Of Electromagnetics
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY