Some sequences hav converging subseguen.ces! Example xj=j" segue nces no en ceS ; 4?... } = { ,", 3'; {1,4,9,16, lim j j? l je IN}. %3D %3D This sey n We will laten that this prove nence has no conu. subseg . Part 1 HW4 imitate the proof below to prove any subsequence of the sequence above also diverges to infinity (not required)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Please prove hw4 in theorem format. 

Some have
sequences
converging subsequen
Example xj=j²
{ j?ljc IN }
ces!
= {',z², 3'; 4?... }
{1,4, 9, 16,
%3D
This seq
lim j
We will
seguence has no conu. subseg.
Part 1 HW4 imitate the proof below to prove any subsequence of the sequence above
also diverges to infinity (not required)
Transcribed Image Text:Some have sequences converging subsequen Example xj=j² { j?ljc IN } ces! = {',z², 3'; 4?... } {1,4, 9, 16, %3D This seq lim j We will seguence has no conu. subseg. Part 1 HW4 imitate the proof below to prove any subsequence of the sequence above also diverges to infinity (not required)
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