Some PCI5 is allowed to dissociate into PCI, and Cl, at 523 K. At equilibrium, [PCl3] = 0.129 M, and [PCl] = [Ch] = 8.03x102 M Additional PCI3 is added so that [PCl3lnew= 0.127 M and the system is allowed to once again reach equilibrium. PCL5(g) PCI3(g) + Cl½(g) K = 5.01×102 at 523 K (a) In which direction will the reaction proceed to reach equilibrium? to the left v (b) What are the new concentrations of reactants and products after the system reaches equilibrium? [PCI3] = M [PCI3] = | M M (Cl2] =|
Some PCI5 is allowed to dissociate into PCI, and Cl, at 523 K. At equilibrium, [PCl3] = 0.129 M, and [PCl] = [Ch] = 8.03x102 M Additional PCI3 is added so that [PCl3lnew= 0.127 M and the system is allowed to once again reach equilibrium. PCL5(g) PCI3(g) + Cl½(g) K = 5.01×102 at 523 K (a) In which direction will the reaction proceed to reach equilibrium? to the left v (b) What are the new concentrations of reactants and products after the system reaches equilibrium? [PCI3] = M [PCI3] = | M M (Cl2] =|
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 62QRT
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![Some PClg is allowed to dissociate into PCl, and Cl, at 523 K. At equilibrium, [PCL3] = 0.129 M, and [PCl] =[Ch] = 8.03×102 M Additional PCI3 is added so that [PC13]new= 0.127 M and the
system is allowed to once again reach equilibrium
PCI3(g) PCI3(g) + Cl2(g)
K= 5.01×10² at 523 K
(a) In which direction will the reaction proceed to reach equilibrium? to the left v
(b) What are the new concentrations of reactants and products after the system reaches equilibrium?
[PCI5] =
[PCI3] =
M
M
[C2] =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa82d5704-6e8c-455f-8edb-5d143da4d2ab%2F49d97f90-64d3-43e7-8ac8-cf864b629805%2F9dq295_processed.png&w=3840&q=75)
Transcribed Image Text:Some PClg is allowed to dissociate into PCl, and Cl, at 523 K. At equilibrium, [PCL3] = 0.129 M, and [PCl] =[Ch] = 8.03×102 M Additional PCI3 is added so that [PC13]new= 0.127 M and the
system is allowed to once again reach equilibrium
PCI3(g) PCI3(g) + Cl2(g)
K= 5.01×10² at 523 K
(a) In which direction will the reaction proceed to reach equilibrium? to the left v
(b) What are the new concentrations of reactants and products after the system reaches equilibrium?
[PCI5] =
[PCI3] =
M
M
[C2] =
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