Some HI is placed in a sealed flask and heated to 776 K. When equilibrium is reached, the flask is found to contain HI (0.288 M), H2 (5.23x10-2 M), and I2 (3.43x10-2 M). What is the value of the equilibrium constant for this reaction at 776 K? 2HI(g) H2(g) + I2(g) K =

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TUTOR Calculate K from Equilibrium Concentrations
Some HI is placed in a sealed flask and heated to 776 K. When equilibrium is reached, the
flask is found to contain HI (0.288 M), H2 (5.23x10-2 M), and I2 (3.43x10-2 M). What is
the value of the equilibrium constant for this reaction at 776 K?
2HI(g) = H2(g) + I2(g)
K =
%D
Transcribed Image Text:TUTOR Calculate K from Equilibrium Concentrations Some HI is placed in a sealed flask and heated to 776 K. When equilibrium is reached, the flask is found to contain HI (0.288 M), H2 (5.23x10-2 M), and I2 (3.43x10-2 M). What is the value of the equilibrium constant for this reaction at 776 K? 2HI(g) = H2(g) + I2(g) K = %D
Expert Solution
Step 1

Given :- 

2HI(g) <=> H2(g) + I2(g) 

[HI] = 0.288 M

 [H2] = 5.23 × 10-2 M

 I2 = 3.43 × 10-2

To Calculate :- value of equilibrium constant (K) 

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