Solving A = Pe¹¹ for P, we obtain P = Ae which is the present value of the amount A due in t years if money earns interest at an annual nominal rate r compounded continuously. (A) Graph P=9,000€ -0.061 Ost≤80. (B) Find lim9.000e - 0.061 [Guess, using part (A).] [Conclusion: The longer the time until the amount A is due, the smaller is its present value, as we would expect.] (A) Choose the correct graph of P=9,000e-0.061, 0sts 80. & OB. O.C. OD. AF Q Q AP Q AP 9000 9000- 9000- 17: 14: 80 (B) lim 9.000e -0.061_ AP 9000- 0+ 80
Solving A = Pe¹¹ for P, we obtain P = Ae which is the present value of the amount A due in t years if money earns interest at an annual nominal rate r compounded continuously. (A) Graph P=9,000€ -0.061 Ost≤80. (B) Find lim9.000e - 0.061 [Guess, using part (A).] [Conclusion: The longer the time until the amount A is due, the smaller is its present value, as we would expect.] (A) Choose the correct graph of P=9,000e-0.061, 0sts 80. & OB. O.C. OD. AF Q Q AP Q AP 9000 9000- 9000- 17: 14: 80 (B) lim 9.000e -0.061_ AP 9000- 0+ 80
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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