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Solve y (kx √√3) dx + (√3 − kx) dy O a. 2kx + 4√/31n|kx √3- O b. 2kx + 4√3ln|kx c. 2kx + 4√3 ln | kx - 2k In|y| √3 - 2k In ly √3+2k In y yz (kx + k sin (kz²) = C k sin (kz²) = C k sin (kz²) = C √3) cos (kz²) dz = 0

Solve y (kx √√3) dx + (√3 − kx) dy O a. 2kx + 4√/31n|kx √3- O b. 2kx + 4√3ln|kx c. 2kx + 4√3 ln | kx - 2k In|y| √3 - 2k In ly √3+2k In y yz (kx + k sin (kz²) = C k sin (kz²) = C k sin (kz²) = C √3) cos (kz²) dz = 0

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve the differential equation using the separation of variables. Provide a complete solution. Use a handwritten and step-by-step calculation without the use of calculator. Explain the process and simplify your answer.
Solve y (kx √3) dx + (√√3 − kx) dy kx) dy - yz (kx √√3) cos (kz²) dz = 0 + k sin (kz²) = C √√3| − 2k ln |y| √3 - 2k In|y| √3+2k In y - k sin (kz²) = C O a. 2kx + 4√3ln|kx O b. 2kx + 4√/31n|kx O c. 2kx +4√3ln|kx - k sin (kz²) = C
Transcribed Image Text:Solve y (kx √3) dx + (√√3 − kx) dy kx) dy - yz (kx √√3) cos (kz²) dz = 0 + k sin (kz²) = C √√3| − 2k ln |y| √3 - 2k In|y| √3+2k In y - k sin (kz²) = C O a. 2kx + 4√3ln|kx O b. 2kx + 4√/31n|kx O c. 2kx +4√3ln|kx - k sin (kz²) = C
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