Solve y"-2y" + y = 5 with initial conditions y(0) = 1, y'(0) = 0, y"(0) = 0

Q: solve y(4)-3y'''+2y''=e3x  using undetermined coefficient

A:

Q: Solve 2y'' - 5y' - 25y = 0, y(0) = 0, y’(0) = = y(t) = - 37.5

A:

Q: Solve the equation y''' - y'' - 2y'= 0

A:

Q: Determine all solutions. y'= (x-y + 3)²

A:

Q: Find the solution to the equation y' - y = x2y2

A:

Q: Solve y" + (y')² = 0.

A:

Q: Solve IVP Y'=AY, A= (-3 3 Y(0) = 13 2

A:

Q: Solve xy"- y' - 4x³y = 8x³sin(x²).

A:

Q: + ¹² = 4t, where y'(1) = 1 and y(1)=2. 4) Solve y" +

A:

Q: 2yy" = 1 + (y')² 2

A:

Q: Solve y' = 12xy 2х, у(0) — 15 -

A:

Q: Find y'

A: given

Q: Solve: y''' + 6y'" – y' - 30y = 0 y(0) = - 2, y'(0) - 15, y''(0) = 45 y(t) =

A:

Q: Solve: y""-12y"+45y'-50y = 0 y(0) = −3, y'(0) = −11, y'(0) = -53 y(t) =

A:

Q: solve: y'' - 5y' + 4y = 20cos(2x) + 30sin(2x) y(0) = 1 y'(0) = 3

A: We have to solve the differential equation given below : y'' - 5y' + 4y = 20cos(2x) + 30sin(2x) ,…

Q: y (4) + 32y"+256y = 0 y(0) = 2, y'(0) = 0, y"(0) = -16, y""(0) = 128

A:

Q: Solve :     x²y"-2x(1+x)y'+2(1+x)y = x3

A: Given: The second order differential equation is x2y''-2xx+1y'+2x+1y=0

Q: Solve:  y’’’ – 4y’’ + y’ + 6y = 0

A:

Q: y'=(2x+2y+1)/(x+y-1)  Solve the equation.?

A: Consider the given equation. y'=2x+2y+1x+y-1 Put v=x+y in the above function. dvdx=1+dydx

Q: Solve y"" + 3y" + 2y' = 0; y(0) = 5, y'(0) = 2, y" (0) = −3.

A:

Q: Solve y" - 2y" +9y' - 18y = 0.

A: Given differential equation: We have to find the solution of the given differential equation.

Q: Solve the equation y" + 4y = 16, y(0) = 9, y'(0) = -5.

A:

Q: Solve x³y"+6x²y"+4xy' = 0.

A:

Q: Solve y(4) - 25y" = 0

A: