Solve y + 2y + 10y -90( 15), y(0) = 1, y (0)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Please walk me through how to do this problem involving the delta function in a second order differential equation. I have provided both the question and the correct answer. Thank you!

The equation depicted is as follows:

\[ 
y(t) = e^{-t} \cos 3t + \frac{4}{3} e^{-t} \sin 3t - 3 u(t-10) e^{-(t-10)} \sin 3(t-10) + 4 u(t-15) e^{-(t-15)} \sin 3(t-15) 
\]

Explanation:

- This is a function \( y(t) \) that involves exponential decay and trigonometric oscillations.
- The terms \( e^{-t} \cos 3t \) and \( \frac{4}{3} e^{-t} \sin 3t \) represent a combination of exponentially decaying cosine and sine waves.
- The Heaviside step function \( u(t-10) \) activates the third term at \( t = 10 \).
- The term \( -3 u(t-10) e^{-(t-10)} \sin 3(t-10) \) indicates an exponentially decaying sine wave starting at \( t = 10 \).
- Similarly, \( u(t-15) \) activates the fourth term at \( t = 15 \).
- The term \( 4 u(t-15) e^{-(t-15)} \sin 3(t-15) \) describes an exponentially decaying sine wave starting at \( t = 15 \).

This function likely models a physical system's response, such as a damped harmonic oscillator subjected to sudden forces at \( t = 10 \) and \( t = 15 \).
Transcribed Image Text:The equation depicted is as follows: \[ y(t) = e^{-t} \cos 3t + \frac{4}{3} e^{-t} \sin 3t - 3 u(t-10) e^{-(t-10)} \sin 3(t-10) + 4 u(t-15) e^{-(t-15)} \sin 3(t-15) \] Explanation: - This is a function \( y(t) \) that involves exponential decay and trigonometric oscillations. - The terms \( e^{-t} \cos 3t \) and \( \frac{4}{3} e^{-t} \sin 3t \) represent a combination of exponentially decaying cosine and sine waves. - The Heaviside step function \( u(t-10) \) activates the third term at \( t = 10 \). - The term \( -3 u(t-10) e^{-(t-10)} \sin 3(t-10) \) indicates an exponentially decaying sine wave starting at \( t = 10 \). - Similarly, \( u(t-15) \) activates the fourth term at \( t = 15 \). - The term \( 4 u(t-15) e^{-(t-15)} \sin 3(t-15) \) describes an exponentially decaying sine wave starting at \( t = 15 \). This function likely models a physical system's response, such as a damped harmonic oscillator subjected to sudden forces at \( t = 10 \) and \( t = 15 \).
**Problem 43**

Solve the differential equation:

\[ y'' + 2y' + 10y = -9\delta(t - 10) + 12\delta(t - 15) \]

with initial conditions \( y(0) = 1 \) and \( y'(0) = 3 \).

---

**Description:**

This problem involves solving a second-order linear differential equation with constant coefficients. The right side of the equation contains Dirac delta functions, \(\delta(t - 10)\) and \(\delta(t - 15)\), which represent impulse inputs applied at times \(t = 10\) and \(t = 15\), respectively. The equation is subject to the initial conditions \( y(0) = 1 \) and \( y'(0) = 3 \).

The goal is to determine the function \(y(t)\) that satisfies the differential equation and respects the given conditions.
Transcribed Image Text:**Problem 43** Solve the differential equation: \[ y'' + 2y' + 10y = -9\delta(t - 10) + 12\delta(t - 15) \] with initial conditions \( y(0) = 1 \) and \( y'(0) = 3 \). --- **Description:** This problem involves solving a second-order linear differential equation with constant coefficients. The right side of the equation contains Dirac delta functions, \(\delta(t - 10)\) and \(\delta(t - 15)\), which represent impulse inputs applied at times \(t = 10\) and \(t = 15\), respectively. The equation is subject to the initial conditions \( y(0) = 1 \) and \( y'(0) = 3 \). The goal is to determine the function \(y(t)\) that satisfies the differential equation and respects the given conditions.
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