Solve X1- 19 -4 11 -8 X1 -5 3 15 15 14 X2 10 19 -9 6 9 -9 X3 -10 18 -3 17 8 X4 18 20 6 15 X5 14 9,

Q: 2x+1=5

A: To solve for x

Q: 15

A:

Q: x2 + 5x - 6 = 0

A:

Q: 2x+3=24. find x

A:

Q: 2x-6=0,find x

A: Given equation is Algebraic equations we will find the solution using airthmetic techniques

Q: Solve x2+ x + 1= 0

A: The given equation is,

Q: x + x2 = 0

A:

Q: 3x-(4+5x)=12

A: We will find the value of x.

Q: x=7, x2-2x+5=

A:

Q: 10b+3x=13  x 3

A: for given equation we get 10b+3x=39 that is 3x=39-10b

Q: 4x+12x=320 find x

A: Given that 4x+12x=320x = ?

Q: x2+y2=25

A:

Q: find the value of x 2х - 8 x+2 2х- 5 x+1

A: Using segment relationship a×b=c×d.

Q: X+5=-4 solve for x

A: Solve for x

Q: Solve For b0

A: For this right angled triangle, sinθ=ac

Q: x2-x+4=0

A: Given equation is

Q: x+4y=6,3y=12

A: Given,  x+4y=6 3y=12

Q: Solve 2x+x +0

A: Given that : To solve 2x+x +0

Q: X-2x+5=0

A: X-2X+5=0 So This implies (x-2x)+5=0 Which also implies (-x) +5=0 So If we transfer x to the other…

Q: Solve X+3 12

A:

Q: 2X+3=9.X=

A: Solution

Q: 2x+4=8 find x

A:

Q: X+2x=4

A: Solve using basic concept of mathematical operations.

Q: X2+x-35=0

A: It is given that, x2+x-35=0 We have to find the value of x.

Q: 4x+2=25 x=?

A:

Q: 6x=47 x=?

A: