Solve using the additive law of probability: A monkey is to demonstrate that she recognizes colors by tossing one red, one black, one white ball, one orange ball, and one purple ball into boxes of the same repsective colors, one ball to a box. If the monkey has not learned the colors and merely tosses one ball into each box at random, find the probabilities of the following results: a. There are no color matches.
Solve using the additive law of
A monkey is to demonstrate that she recognizes colors
by tossing one red, one black, one white ball, one orange ball, and one purple ball into boxes of
the same repsective colors, one ball to a box. If the monkey has
not learned the colors and merely tosses one ball into each box
at random, find the probabilities of the following results:
a. There are no color matches.
b. There is exactly one color match.
a)
The problem involves a monkey tossing 5 different colored balls into 5 different colored boxes. The goal is to find the probabilities of two specific outcomes:
a. There are no color matches.
b. There is exactly one color match.
Balls: There are 5 balls of different colors: red, black, white, orange, and purple.
Boxes: There are 5 boxes, each of the same respective colors as the balls.
- There are 5 distinct balls to toss into 5 distinct boxes, so the total number of permutations is
- The number of derangements
represents the number of permutations where no element appears in its original position. In this case, we want to calculate
- The probability of no color matches is given by the number of derangements divided by the total permutations.
- Probability(no color matches)
Now, calculate:
- !5 = 44 (number of derangements of 5 elements)
- 5! = 120 (total permutations)
Probability(no color matches)
So, the probability of no color matches is
Step 5: Understand The Probability of Exactly One Color Match:
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