Solve using Gaussian Elimination with back-substitution or Gauss Jordan 349 630 19 - 45 등 - 공 + 음프 139 %3D 150 O z =, = -, zs = - %3D %3D %3D %3D 22 = - 23 = %3D %3! O z1 = , *2 = - #3 = %3D
Solve using Gaussian Elimination with back-substitution or Gauss Jordan 349 630 19 - 45 등 - 공 + 음프 139 %3D 150 O z =, = -, zs = - %3D %3D %3D %3D 22 = - 23 = %3D %3! O z1 = , *2 = - #3 = %3D
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.1: Systems Of Equations
Problem 19E
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![Solve using Gaussian Elimination with back-substitution or Gauss Jordan
349
630
19
45
139
150
O ¤1 =, x2 =
*2 = -, *3 = -
= t¤ O
%3D
%3D
Oz =, 2 =- z3 = }
%3D
O z1 =, 2 = -, z3 =
%3D
%3D
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb28b4845-2cf8-47d5-be9f-7cfb4b1b7d89%2F41a8450f-a846-46ea-b285-ea1fa8d13455%2Fvg48b4g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Solve using Gaussian Elimination with back-substitution or Gauss Jordan
349
630
19
45
139
150
O ¤1 =, x2 =
*2 = -, *3 = -
= t¤ O
%3D
%3D
Oz =, 2 =- z3 = }
%3D
O z1 =, 2 = -, z3 =
%3D
%3D
%3D
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