Solve using Gaussian Elimination with back-substitution or Gauss Jordan 349 630 19 - 45 등 - 공 + 음프 139 %3D 150 O z =, = -, zs = - %3D %3D %3D %3D 22 = - 23 = %3D %3! O z1 = , *2 = - #3 = %3D

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.1: Systems Of Equations
Problem 19E
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Solve using Gaussian Elimination with back-substitution or Gauss Jordan
349
630
19
45
139
150
O ¤1 =, x2 =
*2 = -, *3 = -
= t¤ O
%3D
%3D
Oz =, 2 =- z3 = }
%3D
O z1 =, 2 = -, z3 =
%3D
%3D
%3D
Transcribed Image Text:Solve using Gaussian Elimination with back-substitution or Gauss Jordan 349 630 19 45 139 150 O ¤1 =, x2 = *2 = -, *3 = - = t¤ O %3D %3D Oz =, 2 =- z3 = } %3D O z1 =, 2 = -, z3 = %3D %3D %3D
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