Solve using Cramer's Rule: (2x z = 14 3x - y + 5z = 0 4x +2y + 3z = -2

Q: 3x: - 2x2 + 2x3 = 0 6. Solve *, + 2x2 – 3x3 4x1 + x2 + 2x3 = 0 = 0. by Cramer's rule

A: Given that  By solving the equations by cramers rule

Q: Find the roots of 4x5 – 16x4 + 17x3 – 19x2 + 13x – 3 = 0.

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Q: Solve for a+c+h+i in the following: а b c][3 4 2 -12 2 d Lg _h f||6 2 -1| = -2. e 4 -2 -9 L2 12 8.

A: The detailed solution of the problem is given in the next steps.

Q: Find x and y if (-3x - 9) + 4i = 6 + (3y - 2)i.

A: Given that,  (-3x - 9) + 4i = 6 + (3y - 2)i To solve for x and y, need to use below property of…

Q: 4x+2y=2 1.) 2x+2y=4

A: The given system of equation is: 4x+2y=22x+2y=4

Q: Which equation has exactly one solution? CLEAR 6x +5-3x = -3x +5+6x 6x + 5 - 3x = 3x +5-3z 6x +10…

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Q: Make a change of variable, x = Py, that transforms the quadratic form x? + 10xjx2 +x; into a…

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Q: dx x²V(x² -4) Select one: a, 4x b. Vx? - 4) + C C. -Vx? -4) + C 2x d. Vx² - 4) 21 wwm + C 2x

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Q: 2x- 3x-2 6x + 3x? + 2x+1 2x- 3x-2 6x + 3x + 2x+1

A: Explanation of the answer is as follows

Q: Solve using Cramer's rule -4a+2b-9c=2 3a+4b+c=5 a-3b+2c=8

A: Cramer's rule is used to solve a set of linear equation

Q: sinh e Incot3x h- dx St 1+9x²

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Q: Solve for x for 5y+2y=14-6x

A: We need to find an expression for x in terms of y of the given expression 5y+2y=14-6x.

Q: ve : (2a²t – 2æ³) dt + (4æ³ – 6x²t + 2æt?) dæ = 0 | x - c 2x* + c 4 Option 1 Option 2 4x* + c a* +c…

A: Solving the differential equation by grouping of terms.

Q: x-y + 4z=0 8x+y-z=0 7x+2y-5z = 0

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Q: d) 5(2¤ – 3)(3x – 4)(5x – 2) = 0 %3D -

A: The objective is to solve the above expression.

Q: solve this by cartesian product

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Q: Express 2e3+in6 in rectangular form.

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Q: 2x+3x₂-x₂ = 7 3. Use Cramer's rule to solve 3x, -5x₂ =4 x₁ + x₂ = 5

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Q: Complete the square: x²+x+49/36 x²-x+ 14/5 x²+x+ 1/9 = (x+ 7/6 = (x+ = (x+ = -5/14 1/3 )². )². )².

A: We need to complete the square.

Q: Use Cramer's rule and solve 6x-4z=26 7x+8y+5z=122 9x-9y=54

A: Use Cramer’srule and solve.

Q: 。 3 o Z -2x₁ + 3x3 = 13 X2 — 3x4 = 0 2x1 + 3x2 - 2x3 = 0 -3x3 + 2x4 = -15

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Q: solve by using cramers rule  {2x-5y=17 {3x+3y=-6

A: To find the solutions x, y by Cramer's rule

Q: Subtract. (5x* +6x°-2)- (3x² - 5x +7) (5x* + 6x° - 2)- (3x- 5x + 7) = (Simplify your answer.) %3D

A: (5x4+6x3-2)-(3x2-5x+7) =5x4+6x3-2-3x2+5x-7 =5x4+6x3-3x2+5x-9

Q: If AΦB = AB - B find -2Φ3

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Q: Find a + b, 2a + 3b, a = 3i - 5j + 3k, b = 2j - k a+b= 2a + 3b = X X

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Q: Solve (D? – 3D + 2) y cos (e-)

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