Solve triangle ABC if ZA = 42.7°, a = 184.9, and b = 248.6. sin B (round answer to 5 decimal places) There are two possible angles B between 0° and 180° with this value for sine. Find the two angles, and report them so that ZB1 is the acute angle. ZB1 = and ZB2 = (round these and all remaining answers to 1 decimal place) Thus, two triangles satisfy the given conditions: triangle A1 B1C1 and triangle A2B2C2. Solve the first triangle: A1B1C1 ZC1 = and c1 Solve the second triangle: A2B2C2 ZC2 = and c2 =

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