Solve this equation to show that the stationary path is a sin wr 262 y=a sinh (@(2 −1))+ßsinh(@(z−2)) . where α = B = 1 sinh. 1 sinhw 1+ a sin 2w 2w² b cosh w 2w b cosh 2w W a sin w 2w² + bx cosh wr 2w

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Solve this equation to show that the stationary path is
a sin wa
262
y=a sinh (@(z − 1)) +ßsinh(@(2 − 2))
-
where
α =
=
1
sinhw
1
sinh
1+
a sin 2w
26²
b cosh w
2w
b cosh 2w
a sin w
262
W
]
+
bx cosh wx
2w
Transcribed Image Text:Solve this equation to show that the stationary path is a sin wa 262 y=a sinh (@(z − 1)) +ßsinh(@(2 − 2)) - where α = = 1 sinhw 1 sinh 1+ a sin 2w 26² b cosh w 2w b cosh 2w a sin w 262 W ] + bx cosh wx 2w
Let a,
is
b and w be constants, with w‡0.
the
Euler-Lagrange equation for the functional
2
S[y] = [² da (y² + w²y² + 2y(a sin wa + b sinhwa)),
1
y(1) = 0, y(2) = 1,
y" - w²y = a sin wx+bsinh wx, y(1) = 0, y(2) = 1.
2
Transcribed Image Text:Let a, is b and w be constants, with w‡0. the Euler-Lagrange equation for the functional 2 S[y] = [² da (y² + w²y² + 2y(a sin wa + b sinhwa)), 1 y(1) = 0, y(2) = 1, y" - w²y = a sin wx+bsinh wx, y(1) = 0, y(2) = 1. 2
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