Solve the value of x in the given equation _by Jacobi and Gauss-Seidel Method. 13x2 + 4x3 = 111 4x1 + 22x2 – 13x3 = -128 8x. + 8x + 17x, = 10 19х, — -
Solve the value of x in the given equation _by Jacobi and Gauss-Seidel Method. 13x2 + 4x3 = 111 4x1 + 22x2 – 13x3 = -128 8x. + 8x + 17x, = 10 19х, — -
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Solve the value of x in the given equation by
Jacobi and Gauss-Seidel Method.
19х1 — 13х, + 4х3 3 111
13x, + 4x3 = 111
4x1 + 22x, – 13x, = –128
- 13x3
8x1 + 8x, + 17x3 = 10
=D10
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