Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![Solve the system of linear equations and check any solution algebraically.
2x
2y - 8z = -7
-3x + 2y + 8z =
1
х — у — 52%3D —5
Step 1
Since the leading coefficient of the third equation is 1, interchange the third equation with the first equation.
y - 5z = -5
- 3x + 2y + 8z =
2х - 2у — 82 %3D -7
Equation 1
Equation 2
Equation 3
X -
1
Adding 3 times Equation 1 to Equation 2 produces a new second equation. Adding -2 times Equation 1 to
Equation 3 produces a new third equation.
y - 5z = -5
Equation 1
7z =
Equation 2
2z =
Equation 3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7ba61890-9fab-4450-9896-917b96677c7a%2F88f8b5b4-0770-4d96-b717-62c66f02450e%2F07xs8mp_processed.png&w=3840&q=75)
Transcribed Image Text:Solve the system of linear equations and check any solution algebraically.
2x
2y - 8z = -7
-3x + 2y + 8z =
1
х — у — 52%3D —5
Step 1
Since the leading coefficient of the third equation is 1, interchange the third equation with the first equation.
y - 5z = -5
- 3x + 2y + 8z =
2х - 2у — 82 %3D -7
Equation 1
Equation 2
Equation 3
X -
1
Adding 3 times Equation 1 to Equation 2 produces a new second equation. Adding -2 times Equation 1 to
Equation 3 produces a new third equation.
y - 5z = -5
Equation 1
7z =
Equation 2
2z =
Equation 3
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