Solve the system of equations using matrices. Use the Gaussian elimination method with back-substitution. x + y z = -5 3x y + z = -7 -x + 3y - 2z = 1 Use the Gaussian elimination method to obtain the matrix in row-echelon form. Choose the correct answer below. OA. O C. ! 1 1 - 1 - 5 0 1 - 1-2 0 0 1 4 100-5 1 0 -2 4 - 1 - 1 1 1 ... The solution set is {10}. (Simplify your answers.) O B. O D. -1 -1 0 - 1 0 0 1 -5 1 -2 - 1 4 1 1-5 1 01-2 1 0 0 4 1

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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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**Solving Systems of Equations Using Matrices**

To solve the system of equations using matrices, we'll apply the Gaussian elimination method with back-substitution. Consider the following system:

\[ 
\begin{cases} 
x + y - z = -5 \\ 
3x - y + z = -7 \\ 
-x + 3y - 2z = 1 
\end{cases} 
\]

**Objective:**

Use Gaussian elimination to transform the system into a row-echelon form matrix. Choose the correct matrix from the options provided.

**Options for Row-Echelon Form:**

- **Option A:**
  \[
  \begin{bmatrix}
  1 & 1 & -1 & -5 \\
  0 & 1 & -1 & -2 \\
  0 & 0 & 1 & 4 \\
  \end{bmatrix}
  \]

- **Option B:**
  \[
  \begin{bmatrix}
  -1 & -1 & 1 & -5 \\
  0 & -1 & 1 & -2 \\
  0 & 0 & -1 & 4 \\
  \end{bmatrix}
  \]

- **Option C:**
  \[
  \begin{bmatrix}
  1 & 0 & 0 & -5 \\
  -1 & 1 & 0 & -2 \\
  -1 & 1 & 1 & 4 \\
  \end{bmatrix}
  \]

- **Option D:**
  \[
  \begin{bmatrix}
  1 & 1 & -5 & -1 \\
  0 & 1 & -2 & -1 \\
  0 & 0 & 1 & 4 \\
  \end{bmatrix}
  \]

**Solution Set Format:**

Determine the solution set in the form \(\{ ( \Box , \Box , \Box ) \} \), simplifying your answers.

**Instructions:**

1. Use the Gaussian elimination to reduce the original matrix into the row-echelon form.
2. After achieving the row-echelon form, identify the correct matrix from the options.
3. Solve for \((x, y, z)\) using back-substitution to complete the solution set, ensuring simplification of the answers.
Transcribed Image Text:**Solving Systems of Equations Using Matrices** To solve the system of equations using matrices, we'll apply the Gaussian elimination method with back-substitution. Consider the following system: \[ \begin{cases} x + y - z = -5 \\ 3x - y + z = -7 \\ -x + 3y - 2z = 1 \end{cases} \] **Objective:** Use Gaussian elimination to transform the system into a row-echelon form matrix. Choose the correct matrix from the options provided. **Options for Row-Echelon Form:** - **Option A:** \[ \begin{bmatrix} 1 & 1 & -1 & -5 \\ 0 & 1 & -1 & -2 \\ 0 & 0 & 1 & 4 \\ \end{bmatrix} \] - **Option B:** \[ \begin{bmatrix} -1 & -1 & 1 & -5 \\ 0 & -1 & 1 & -2 \\ 0 & 0 & -1 & 4 \\ \end{bmatrix} \] - **Option C:** \[ \begin{bmatrix} 1 & 0 & 0 & -5 \\ -1 & 1 & 0 & -2 \\ -1 & 1 & 1 & 4 \\ \end{bmatrix} \] - **Option D:** \[ \begin{bmatrix} 1 & 1 & -5 & -1 \\ 0 & 1 & -2 & -1 \\ 0 & 0 & 1 & 4 \\ \end{bmatrix} \] **Solution Set Format:** Determine the solution set in the form \(\{ ( \Box , \Box , \Box ) \} \), simplifying your answers. **Instructions:** 1. Use the Gaussian elimination to reduce the original matrix into the row-echelon form. 2. After achieving the row-echelon form, identify the correct matrix from the options. 3. Solve for \((x, y, z)\) using back-substitution to complete the solution set, ensuring simplification of the answers.
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