Solve the system and answer the problem's question. The system S40x + 60y = 1920 l10x + 100y = 1160 can be solved by addition. We'll multiply the second equation by -4 and then add equations to eliminate x. ( 40x + 60y = 1920 ( 10x + 100y = 1160 No change Multiply by -4. 40x + 60y 1920 %3D -40x 400y -4640 Add: -340y = -2720 -2720 = 8 y = -340 Now we can find the value of x by back-substituting 8 for yin either of the system's equations. 10x + 100y = 1160 We'll use the second equation. 10x + 100(8) 1160 Back-substitute 8 for y. 10x + 800 1160 Multiply. 10x = 360 Subtract 800 from both sides. = 36 Divide both sides by 10.
Solve the system and answer the problem's question. The system S40x + 60y = 1920 l10x + 100y = 1160 can be solved by addition. We'll multiply the second equation by -4 and then add equations to eliminate x. ( 40x + 60y = 1920 ( 10x + 100y = 1160 No change Multiply by -4. 40x + 60y 1920 %3D -40x 400y -4640 Add: -340y = -2720 -2720 = 8 y = -340 Now we can find the value of x by back-substituting 8 for yin either of the system's equations. 10x + 100y = 1160 We'll use the second equation. 10x + 100(8) 1160 Back-substitute 8 for y. 10x + 800 1160 Multiply. 10x = 360 Subtract 800 from both sides. = 36 Divide both sides by 10.
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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