Solve the recurrence relation subject to the initial conditions. F(1) = 8, F(2) = 18, and F(n) = 6F(n − 1) − 5F(n − 2) for n ≥ 3

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Solve the recurrence relation subject to the initial conditions.

F(1) = 8, F(2) = 18, and F(n) = 6F(n − 1) − 5F(n − 2) for n ≥ 3

Expert Solution
Step 1

Given, recurrence relation 

                F(n) = 6F(n − 1) − 5F(n − 2) for n ≥ 3

with initial condition

                F(1) = 8, F(2) = 18

Now, the characteristic equation of given recurrence relation is

     

        r2-6r+5 = 0r2-1r-5r+5 = 0r(r-1)-5(r-1)=0(r-1)(r-5)=0(r-1) = 0 or (r-5) = 0  if (r-1)=0 r=1  if (r-5)=0 r=5     

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