Solve the quadratic by factoring. 8х - 63 -10x |

Algebra and Trigonometry (6th Edition)
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Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Solving Quadratic Equations by Factoring

This tutorial will guide you through the steps to solve a quadratic equation by factoring. Below is an example problem and its solution process.

**Example Problem:**

Solve the quadratic equation by factoring:

\[ x^2 - 8x - 63 = -10x \]

To solve this equation, follow these steps:

1. **Move All Terms to One Side**: 
   Start by combining like terms to set the equation equal to zero:
   \[ x^2 - 8x - 63 + 10x = 0 \]
   Simplify the equation:
   \[ x^2 + 2x - 63 = 0 \]

2. **Factor the Quadratic Expression**:
   The quadratic expression \( x^2 + 2x - 63 \) needs to be factored. We need to find two numbers that multiply to -63 and add to 2. These numbers are 9 and -7.
   Write the expression as:
   \[ (x + 9)(x - 7) = 0 \]

3. **Set Each Factor Equal to Zero**:
   Set each factor equal to zero and solve for x:
   \[ x + 9 = 0 \quad \Rightarrow \quad x = -9 \]
   \[ x - 7 = 0 \quad \Rightarrow \quad x = 7 \]

Therefore, the solutions to the quadratic equation \( x^2 + 2x - 63 = 0 \) are:

\[ x = -9 \quad \text{or} \quad x = 7 \]

Once you've worked through the solution, enter your answer in the space provided and submit it to check your result.

**Answer:**
\[ x = \boxed{} \]

[Submit Answer]

By following these steps, you can solve any quadratic equation by factoring. Practice with additional problems to master this fundamental algebra skill.
Transcribed Image Text:### Solving Quadratic Equations by Factoring This tutorial will guide you through the steps to solve a quadratic equation by factoring. Below is an example problem and its solution process. **Example Problem:** Solve the quadratic equation by factoring: \[ x^2 - 8x - 63 = -10x \] To solve this equation, follow these steps: 1. **Move All Terms to One Side**: Start by combining like terms to set the equation equal to zero: \[ x^2 - 8x - 63 + 10x = 0 \] Simplify the equation: \[ x^2 + 2x - 63 = 0 \] 2. **Factor the Quadratic Expression**: The quadratic expression \( x^2 + 2x - 63 \) needs to be factored. We need to find two numbers that multiply to -63 and add to 2. These numbers are 9 and -7. Write the expression as: \[ (x + 9)(x - 7) = 0 \] 3. **Set Each Factor Equal to Zero**: Set each factor equal to zero and solve for x: \[ x + 9 = 0 \quad \Rightarrow \quad x = -9 \] \[ x - 7 = 0 \quad \Rightarrow \quad x = 7 \] Therefore, the solutions to the quadratic equation \( x^2 + 2x - 63 = 0 \) are: \[ x = -9 \quad \text{or} \quad x = 7 \] Once you've worked through the solution, enter your answer in the space provided and submit it to check your result. **Answer:** \[ x = \boxed{} \] [Submit Answer] By following these steps, you can solve any quadratic equation by factoring. Practice with additional problems to master this fundamental algebra skill.
## Solving Quadratics by Factoring: Step-by-Step Example

To solve the quadratic equation by factoring, follow this step-by-step guide.

### Step 1: Set the quadratic expression to zero

Start with your quadratic equation. For this example we have:

\[ x^2 + 14x - 25 = 10x - 4 \]

First, move all the terms to one side to set the equation to zero:

\[ x^2 + 14x - 25 - 10x + 4 = 0 \]

Simplify the expression:

\[ x^2 + 4x - 21 = 0 \]

### Step 2: Factor the quadratic equation

Next, factor the quadratic expression. For this example, the quadratic expression \( x^2 + 4x - 21 \) factors into:

\[ (x + 7)(x - 3) = 0 \]

### Step 3: Set each factor to zero and solve

After factoring the equation, set each factor equal to zero to solve for \( x \):

\[ x + 7 = 0 \quad \text{or} \quad x - 3 = 0 \]

Then, solve each equation:

1. For \( x + 7 = 0 \):

\[ x = -7 \]

2. For \( x - 3 = 0 \):

\[ x = 3 \]

### Solution

The solutions to the quadratic equation \( x^2 + 4x - 21 = 0 \) are:

\[ x = -7 \quad \text{or} \quad x = 3 \]

This step-by-step example illustrates how to solve a quadratic equation by factoring, setting each factor to zero, and solving for \( x \).
Transcribed Image Text:## Solving Quadratics by Factoring: Step-by-Step Example To solve the quadratic equation by factoring, follow this step-by-step guide. ### Step 1: Set the quadratic expression to zero Start with your quadratic equation. For this example we have: \[ x^2 + 14x - 25 = 10x - 4 \] First, move all the terms to one side to set the equation to zero: \[ x^2 + 14x - 25 - 10x + 4 = 0 \] Simplify the expression: \[ x^2 + 4x - 21 = 0 \] ### Step 2: Factor the quadratic equation Next, factor the quadratic expression. For this example, the quadratic expression \( x^2 + 4x - 21 \) factors into: \[ (x + 7)(x - 3) = 0 \] ### Step 3: Set each factor to zero and solve After factoring the equation, set each factor equal to zero to solve for \( x \): \[ x + 7 = 0 \quad \text{or} \quad x - 3 = 0 \] Then, solve each equation: 1. For \( x + 7 = 0 \): \[ x = -7 \] 2. For \( x - 3 = 0 \): \[ x = 3 \] ### Solution The solutions to the quadratic equation \( x^2 + 4x - 21 = 0 \) are: \[ x = -7 \quad \text{or} \quad x = 3 \] This step-by-step example illustrates how to solve a quadratic equation by factoring, setting each factor to zero, and solving for \( x \).
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