Solve the problem. The floor of a rectangular room is to be tiled with foot square tiles along a wall. How many tiles will be needed along the wall? 2 tiles 18² tiles 19 tiles 21 tiles foot
Solve the problem. The floor of a rectangular room is to be tiled with foot square tiles along a wall. How many tiles will be needed along the wall? 2 tiles 18² tiles 19 tiles 21 tiles foot
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
![**Solve the problem.**
The floor of a rectangular room is to be tiled with \( \frac{1}{3} \) foot square tiles along a \( 6 \frac{3}{8} \) foot wall. How many tiles will be needed along the wall?
- \( 2 \frac{1}{8} \) tiles
- \( 18 \frac{3}{8} \) tiles
- \( 19 \frac{1}{8} \) tiles
- 21 tiles
**Explanation:**
To solve this problem, divide the length of the wall by the size of the tile:
1. Convert \( 6 \frac{3}{8} \) feet to an improper fraction:
\[
6 \frac{3}{8} = \frac{51}{8}
\]
2. Divide by the size of each tile, \( \frac{1}{3} \) foot:
\[
\text{Number of tiles} = \frac{\frac{51}{8}}{\frac{1}{3}} = \frac{51}{8} \times \frac{3}{1} = \frac{153}{8}
\]
3. Convert \( \frac{153}{8} \) to a mixed number:
\[
\frac{153}{8} = 19 \frac{1}{8}
\]
The answer is \( 19 \frac{1}{8} \) tiles.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb30d7fc0-4739-4205-b977-e5697f99a5bd%2Fb7f74722-560e-4ff3-a88f-467199bcabc3%2F7nnbgy4_processed.png&w=3840&q=75)
Transcribed Image Text:**Solve the problem.**
The floor of a rectangular room is to be tiled with \( \frac{1}{3} \) foot square tiles along a \( 6 \frac{3}{8} \) foot wall. How many tiles will be needed along the wall?
- \( 2 \frac{1}{8} \) tiles
- \( 18 \frac{3}{8} \) tiles
- \( 19 \frac{1}{8} \) tiles
- 21 tiles
**Explanation:**
To solve this problem, divide the length of the wall by the size of the tile:
1. Convert \( 6 \frac{3}{8} \) feet to an improper fraction:
\[
6 \frac{3}{8} = \frac{51}{8}
\]
2. Divide by the size of each tile, \( \frac{1}{3} \) foot:
\[
\text{Number of tiles} = \frac{\frac{51}{8}}{\frac{1}{3}} = \frac{51}{8} \times \frac{3}{1} = \frac{153}{8}
\]
3. Convert \( \frac{153}{8} \) to a mixed number:
\[
\frac{153}{8} = 19 \frac{1}{8}
\]
The answer is \( 19 \frac{1}{8} \) tiles.
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