Solve the problem. Round your answer, if appropriate. Boyle's law states that if the temperature of a gas remains constant, then PL = C, where P = pressure, V= volume, and c is a constant. Given a quantity of gas at constant temperature, if V is decreasing at a rate of 14 in. /sec, at what rate is P increasing when P = 60 lb/in.? and V = 40 in.? (Do not round your answer.)

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Solve the problem. Round your answer, if appropriate.
Boyle's law states that if the temperature of a gas remains constant, then PV
= C, where P=pressure, V=volume, and c is a constant. Given a quantity of gas
at constant temperature, if V is decreasing at a rate of 14 in. /sec, at what
rate is P increasing when P= 60 lb/in. and V = 40 in.? (Do not round your
%3D
answer.)
Transcribed Image Text:Solve the problem. Round your answer, if appropriate. Boyle's law states that if the temperature of a gas remains constant, then PV = C, where P=pressure, V=volume, and c is a constant. Given a quantity of gas at constant temperature, if V is decreasing at a rate of 14 in. /sec, at what rate is P increasing when P= 60 lb/in. and V = 40 in.? (Do not round your %3D answer.)
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