Solve the problem. 3) The function given by y=f(x) shows the value of $5000 invested at 5% interest compounded continuously, x years after the money was originally invested. Find the average amount earned per year between the 20th year and 25th year. y (Syrs f(x) = mx +b Value ($) 32000+ 28000- 24000+ 20000+ 16000- 12000- (20, 13,591) (15, 10,585) (30, 22,408) (25, 17,452) (20,13,591) (25, 17,452) 3861 lisail sovigodi of follerng sail to se 5 novig $772.2/per suil a'lo se

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Solve the problem type question. I’m stuck on how to use the formula for solving the average amount earned per year between the 20th and 25th year.
Value ($)
32000-
Solve the problem.
3) The function given by y=f(x) shows the value of $5000 invested at 5% interest
compounded continuously, x years after the money was originally invested. Find
the average amount earned per year between the 20th year and 25th year.
y
Surs
FG
f(x) = mx +b
28000-
24000+
20000+
16000-
12000-
-N
4000+
8000+ (10, 8244)
(15, 10,585)
5
-int
yint= (0,-5)
(20, 13,591)
(5,6420)
(30, 22,408)
(25, 17,452) novi
10 15 20
Number of Years
25
(20,13,591)
(25, 17,452)
3861
5
evig i snit
lionil novied) of fellesaq sallato sgole se
772.2/perg snil a lo sgole se
(2)
30 X
1
3)
Transcribed Image Text:Value ($) 32000- Solve the problem. 3) The function given by y=f(x) shows the value of $5000 invested at 5% interest compounded continuously, x years after the money was originally invested. Find the average amount earned per year between the 20th year and 25th year. y Surs FG f(x) = mx +b 28000- 24000+ 20000+ 16000- 12000- -N 4000+ 8000+ (10, 8244) (15, 10,585) 5 -int yint= (0,-5) (20, 13,591) (5,6420) (30, 22,408) (25, 17,452) novi 10 15 20 Number of Years 25 (20,13,591) (25, 17,452) 3861 5 evig i snit lionil novied) of fellesaq sallato sgole se 772.2/perg snil a lo sgole se (2) 30 X 1 3)
Expert Solution
Step 1

Given that,

Initial Investment (P) = $5000

Rate of interest (r) = 5% compounded continuously.

As we know that amount after x year of original investment is

A=Pe(rx)

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