I need step by step solution with answer , thanks **Solve the problem.**1) A deep sea diving bell is being lowered at a constant rate. After 10 minutes, the bell is at a depth of 300 ft. After 30 minutes, the bell is at a depth of 1900 ft. Use the ordered pairs (10, 300) and (30, 1900) to determine the average rate to lower the bell per minute.**Explanation:**The problem involves calculating the average rate of descent for a deep sea diving bell using the given time and depth data points. The data points are represented as ordered pairs:- (10, 300) represents the time in minutes and depth in feet after 10 minutes.- (30, 1900) represents the time in minutes and depth in feet after 30 minutes.The average rate can be calculated using the formula for the slope of a line: \[\text{Slope} = \frac{y_2 - y_1}{x_2 - x_1}\]Where:- $y_2$ and $y_1$ are the depths at times $x_2$ and $x_1$, respectively.- Here, $x_1 = 10$, $y_1 = 300$, $x_2 = 30$, and $y_2 = 1900$.Substituting the given values:\[\text{Slope} = \frac{1900 - 300}{30 - 10} = \frac{1600}{20} = 80\]Thus, the average rate to lower the bell is 80 feet per minute.

Answered: Image /qna-images/answer/4c177b2b-bcef-4399-b68d-be94c59a09f6.jpg

Solve the problem. 1) A deep sea diving bell is being lowered at a constant rate. After 10 minutes, the bell is at a depth of 300 ft. After 30 minutes the bell is at a depth of 1900 ft. Use the ordered pairs (10, 300) and (30, 1900) to determine the average rate to lower the bell per minute. Q Search hp meh

Solve the problem. 1) A deep sea diving bell is being lowered at a constant rate. After 10 minutes, the bell is at a depth of 300 ft. After 30 minutes the bell is at a depth of 1900 ft. Use the ordered pairs (10, 300) and (30, 1900) to determine the average rate to lower the bell per minute. Q Search hp meh

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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Question

I need step by step solution with answer , thanks

**Solve the problem.**

1) A deep sea diving bell is being lowered at a constant rate. After 10 minutes, the bell is at a depth of 300 ft. After 30 minutes, the bell is at a depth of 1900 ft. Use the ordered pairs (10, 300) and (30, 1900) to determine the average rate to lower the bell per minute.

**Explanation:**

The problem involves calculating the average rate of descent for a deep sea diving bell using the given time and depth data points. The data points are represented as ordered pairs:

- (10, 300) represents the time in minutes and depth in feet after 10 minutes.
- (30, 1900) represents the time in minutes and depth in feet after 30 minutes.

The average rate can be calculated using the formula for the slope of a line:

\[
\text{Slope} = \frac{y_2 - y_1}{x_2 - x_1}
\]

Where:
- $y_2$ and $y_1$ are the depths at times $x_2$ and $x_1$, respectively.
- Here, $x_1 = 10$, $y_1 = 300$, $x_2 = 30$, and $y_2 = 1900$.

Substituting the given values:

\[
\text{Slope} = \frac{1900 - 300}{30 - 10} = \frac{1600}{20} = 80
\]

Thus, the average rate to lower the bell is 80 feet per minute.

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