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- List the sample space of each experiment. Tossing three coinsThe Commissioner of Health in New York State wanted to study malpractice litigation in New York. A sample of 31 thousand medical records was drawn from a population of 2.7 million patients who were discharged during the year 2009. Using the information obtained from the sample to predict population characteristics with respect to malpractice litigation is an example of ________.A popular Italian eatery has had a dispute among the wait staff regarding the amount of tips waiters receive on the lunch shift and on the dinner shift. Before making any adjustments in schedules or other policies, the restaurant manager wants to estimate the difference in the average tips eamed by waiters on the lunch schedule and on the dinner schedule. To do this, she randomly selected 60 tip reports for lunch servers over the past year and 50 tip reports from dinner servers. The results given below were observed. Assuming equal population variances, develop and interpret an 80% confidence interval estimate for the difference between the population mean tips earned by lunch servers and by dinner servers. Mean Tips St. Dev. Tips Lunch $64.40 $11.90 The mean tips earned Dinner $101.90 $13.02 Let sample 1 be the sample from the lunch servers and let sample 2 be the sample from the dinner servers. The 80% confidence interval is (Round to two decimal places as needed.) 40.57 S (H₁-H₂) =…
- The General Social Survey (GSS) asked this question: “Have you attended religious services in the last week?” Here are the responses for those whose highest degree was high school or above Carry out the chi-square test for the hypothesis of no relationship between the highest degree attained and attendance at religious services in the last week. What do you conclude? Make a table by omitting the column corresponding to those whose highest degree was high school. A) Carry out the chi-square test for the hypothesis of no relationship between the type of advanced degree attained and attendance at religious services in the last week. What do you conclude? B)Make a 2×3 table by omitting the column corresponding to those whose highest degree was high school. Carry out the chi-square test for the hypothesis of no relationship between the type of advanced degree attained and attendance at religious services in the last week. What do you conclude? C) Make a 2×2 table by combining the counts…An automobile dealer conducted a test to determine if the time in minutes needed to complete a minor engine tune-up depends on whether a computerized engine analyzer or an electronic analyzer is used. Because tune-up time varies among compact, intermediate, and full-sized cars, the three types of cars were used as blocks in the experiment. The data obtained follow. Analyzer Computerized Electronic Car Compact 51 42 Intermediate 55 43 Full-sized 62 47 Use ? = 0.05 to test for any significant differences. State the null and alternative hypotheses. H0: ?Computerized ≠ ?ElectronicHa: ?Computerized = ?ElectronicH0: ?Computerized = ?Electronic = ?Compact = ?Intermediate = ?Full-sizedHa: Not all the population means are equal. H0: ?Computerized = ?ElectronicHa: ?Computerized ≠ ?ElectronicH0: ?Compact ≠ ?Intermediate ≠ ?Full-sizedHa: ?Compact = ?Intermediate = ?Full-sizedH0: ?Compact = ?Intermediate = ?Full-sizedHa: ?Compact ≠ ?Intermediate ≠ ?Full-sized Find the value of…A researcher was interested in the effect of home schooling on literacy. Thirteen children who were home-schooled and 13 children who attended a public school participated in a study. The children were matched on age, family SES, and IQ as tested with the WISC (Weschler Inteeligence Scale for Children). The researchers were interested in the number of books the children read each year and so they asked them to recall the titles of the books read in the last 12 months. The researchers hypothesized that children who are home-schooled read more than children who attend public school. Interpret the Excel output obtained at the 5% significance level (a = 0.05). What conclusion can the researchers draw? Write the step 5 answer (formal APA format notation and conclusion; round your answer to 2 decimal places). Home School Public School IET t-Test: Paired Two Sample for Means 12 Home School Public School 6 1 Mean 10.69 7.23 Variance 27.90 20.69 20 18 Observations 13 13 18 10 Pearson…
- A researcher was interested in the effect of home schooling on literacy. Thirteen children who were home-schooled and 13 children who attended a public school participated in a study. The children were matched on age, family SES, and IQ as tested with the WISC (Weschler Inteeligence Scale for Children). The researchers were interested in the number of books the children read each year and so they asked them to recall the titles of the books read in the last 12 months. The researchers hypothesized that children who are home-schooled read more than children who attend public school. Interpret the Excel output obtained at the 5% significance level (a = 0.05). What conclusion can the researchers draw? Write the step 5 answer (formal APA format notation and conclusion; round your answer to 2 decimal places). Home School Public School MET t-Test: Paired Two Sample for Means 4 12 6. Home School Public School 1 Mean 10.69 7.23 3 3 Variance 27.90 20.69 20 18 Observations 13 18 10 Pearson…A forensic psychologist is interested in assessing the prevalence of major depressive disorders among a sample of prison inmates. A random sample of inmates was selected and tested on the MDI (Major Depressive Inventory), a self-report instrument designed to measure levels of depression. Their scores were: 8, 10, 4, 11, 7, 10, 13, 4, 8, 7, 9, 3, 15, 10, 10, 10, & 13. a.) Use descriptive statistics including sample size, skewness, kurtosis, mean, median, mode, range, and standard deviation to describe this sample. Write your results in a paragraph similar to the Results section of a manuscript. b.) If the MDI has a µ = 10, is the depression of prison inmates significantly different than that of the general population? Test with an α = 0.05. c.) What type of error is possible based on the outcome? I need help learning these questions.What is the p-value for the test statistic?A) 0.0165B) 0.0188803968C) 0.168D) 0.0085E) 0.0022854202
- This dataset consists of a sample of female who participated in the RHS in a selected Caribbean country.This document has selected questions as they appeared onthe questionnaire that was administered to collect data on reproductive health of women in aselected Caribbean country. The following are selected questions from a Female Reproductive Health Survey in a CaribbeanIsland.Q102. How old were you on your last birthday? ……………..Q104. How many years did you attend school, not including years spent in infant and basicschool? ……….Q105. With what frequency do you attend religious services?1. At least once per week2. At least once per month3. Less than a month4. Only for special occasions (weddings, funerals, christening)5. Does not attend at allQ106. What were you doing in the past week?1. Working2. Not working but had a job3. Looking for work4. Wanted work and was available5. Keeping house6. Going to school7. On vacation from school8. At home, not keeping house9. Incapable of workQ108.…An automobile dealer conducted a test to determine if the time in minutes needed to complete a minor engine tune-up depends on whether a computerized engine analyzer or an electronic analyzer is used. Because tune-up time varies among compact, intermediate, and full-sized cars, the three types of cars were used as blocks in the experiment. The data obtained follow. Analyzer Computerized Electronic Car Compact 52 43 Intermediate 55 44 Full sized 61 45 Use ? = 0.05 to test for any significant differences. State the null and alternative hypotheses. H0: ?Compact ≠ ?Intermediate ≠ ?Full-sizedHa: ?Compact = ?Intermediate = ?Full-sized H0: ?Compact = ?Intermediate = ?Full-sizedHa: ?Compact ≠ ?Intermediate ≠ ?Full-sized H0: ?Computerized = ?Electronic = ?Compact = ?Intermediate = ?Full-sizedHa: Not all the population means are equal. H0: ?Computerized ≠ ?ElectronicHa: ?Computerized = ?Electronic H0: ?Computerized = ?ElectronicHa: ?Computerized ≠ ?Electronic Find the…he data on the number of chocolate chips per bag for 42 bags of Chips Ahoy! cookies were obtained by the students in an introductory statistics class at the United States Air Force Academy in response to the Chips Ahoy! 1,000 Chips Challenge sponsored by Nabisco, the makers of Chips Ahoy! Use the data collected by the students to answer the following questions and to conduct the analyses required in each part. They found ¯xx¯ = 1261.6 and s = 117.6 a. Determine a 95% confidence interval for the mean number of chips per bag for all bags of Chips Ahoy! cookies. ≤μ≤≤μ≤ b. Interpret your result in words. c. Can you conclude that the average bag of Chips Ahoy! Cookies contain at least 1000 chocolate chips? yes no
