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Solve the PDE. PDE: IC: u(x,0) = 8 sin(x) U₁2u₂+7u= 0, -∞ 0.

Solve the PDE. PDE: IC: u(x,0) = 8 sin(x) U₁2u₂+7u= 0, -∞ 0.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve the PDE. PDE: U₁2u₂+7u= 0, -∞ < x < ∞ and t > 0. IC: u(x,0) = 8 sin(x) Using method of characteristics, you can write this in differential form as: dt/ =dx/ |= du/ Hint: When you get the integration result in the form of In() then you can convert the constant as In (c). Solving by using the initial conditions, we finally get, u =
Transcribed Image Text:Solve the PDE. PDE: U₁2u₂+7u= 0, -∞ < x < ∞ and t > 0. IC: u(x,0) = 8 sin(x) Using method of characteristics, you can write this in differential form as: dt/ =dx/ |= du/ Hint: When you get the integration result in the form of In() then you can convert the constant as In (c). Solving by using the initial conditions, we finally get, u =
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