Solve the partial differential equation u(0, t) = u(π, t) = du Ət - 8²u on the interval [0, π] subject to the boundary conditions 0 and the initial condition Your answer should depend on both x and t. u(x,0) = 4 sin (3x) - 3 sin(10x). u(x, t) = 4sin(3x)e^(-4pi^2t)-3sin(10x)e^(-1
Solve the partial differential equation u(0, t) = u(π, t) = du Ət - 8²u on the interval [0, π] subject to the boundary conditions 0 and the initial condition Your answer should depend on both x and t. u(x,0) = 4 sin (3x) - 3 sin(10x). u(x, t) = 4sin(3x)e^(-4pi^2t)-3sin(10x)e^(-1
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![?u
Ət
Solve the partial differential equation
u(0, t) = u(π, t) = 0 and the initial condition
=
4
Your answer should depend on both x and t.
u(x, t)
J²u
on the interval [0, π] subject to the boundary conditions
Əx²
u(x, 0) = 4 sin (3x) — 3 sin(10x).
4sin(3x)e^(-4pi^2t)-3sin(10x)e^(-11](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7be0278b-c62e-4a22-a818-58df3f094bc2%2Ffad6c100-6591-4b41-bf2a-9bb270961f57%2Fu6pwlp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:?u
Ət
Solve the partial differential equation
u(0, t) = u(π, t) = 0 and the initial condition
=
4
Your answer should depend on both x and t.
u(x, t)
J²u
on the interval [0, π] subject to the boundary conditions
Əx²
u(x, 0) = 4 sin (3x) — 3 sin(10x).
4sin(3x)e^(-4pi^2t)-3sin(10x)e^(-11
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