= Solve the matrix equation AX = B for X. 14 -4 B= A=[-33] ³- (-22) -8 X=

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Title: Solving Matrix Equation AX = B**

**Objective:** Solve the matrix equation \( AX = B \) for \( X \).

**Given:**
\[ A = \begin{bmatrix} 1 & 4 \\ -3 & 5 \end{bmatrix} \]
\[ B = \begin{bmatrix} -4 \\ -22 \end{bmatrix} \]

**Solution:**

To find \( X \), we need to compute the inverse of matrix \( A \) (denoted as \( A^{-1} \)) and then multiply it by \( B \). The formula used is:
\[ X = A^{-1}B \]

**X =**

\[ \begin{bmatrix} \text{[  ]} \\ \text{[  ]} \end{bmatrix} \]

**Instructions:**

1. Calculate the determinant of \( A \).
2. Find the inverse of \( A \) if the determinant is non-zero.
3. Multiply \( A^{-1} \) by \( B \) to get \( X \).

**Conclusion:**

This process will yield the solution \( X \) in matrix form.
Transcribed Image Text:**Title: Solving Matrix Equation AX = B** **Objective:** Solve the matrix equation \( AX = B \) for \( X \). **Given:** \[ A = \begin{bmatrix} 1 & 4 \\ -3 & 5 \end{bmatrix} \] \[ B = \begin{bmatrix} -4 \\ -22 \end{bmatrix} \] **Solution:** To find \( X \), we need to compute the inverse of matrix \( A \) (denoted as \( A^{-1} \)) and then multiply it by \( B \). The formula used is: \[ X = A^{-1}B \] **X =** \[ \begin{bmatrix} \text{[ ]} \\ \text{[ ]} \end{bmatrix} \] **Instructions:** 1. Calculate the determinant of \( A \). 2. Find the inverse of \( A \) if the determinant is non-zero. 3. Multiply \( A^{-1} \) by \( B \) to get \( X \). **Conclusion:** This process will yield the solution \( X \) in matrix form.
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