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Solve the linear system using the Gauss-Jordan elimination method. 3х +3у +3 %0 - 2x +2y -6 =0 The solution of the system is x= y= (Simplify your answers.)

Solve the linear system using the Gauss-Jordan elimination method. 3х +3у +3 %0 - 2x +2y -6 =0 The solution of the system is x= y= (Simplify your answers.)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve the linear system using the Gauss-Jordan elimination method. 3x + 3y +3 = 0 2x +2y -6 =0 The solution of the system is x= ,y= (Simplify your answers.)
Transcribed Image Text:Solve the linear system using the Gauss-Jordan elimination method. 3x + 3y +3 = 0 2x +2y -6 =0 The solution of the system is x= ,y= (Simplify your answers.)
Expert Solution
Step 1

Given system of equation

3x+3y+3=0−2x+2y−6=0........1

We have to find the solution if the given system of equations (1) by Gauss-Jordan elimination method.

System of equation (1) can be written as

3x+3y=−3−2x+2y=6........2

Write augmented matrix A|b

A|b=33−3−226

 

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