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Solve the linear system of equations. -59x - 2y 2х — Зу %3D-89 1 Step 1 of 3 Determine the appropriate constant to multiply by. Your goal is to solve the system using the elimination method. The coefficients of x have opposite signs. The least common multiple, or LCM, of the coefficients, 2 and -59, is 118. Multiply each equation by the number that will make the coefficients -118 and 118. -59x – 2y = 2х — Зу %3 —89 1 2(-59x – 2y) = (No Response) 2 (1) 59(2x – 3y) = (No Response) 59 (-89) -118x – |(No Response) y = 2 118x – (No Response) 177 y = -5,251 Step 2 of 3 The system from Step 1 has a variable with opposite coefficients. Add the equations and solve for the other variable. Add the equations to eliminate x. Then use the division property of equality to solve for y. -118x 4y = 2 118x - 177y = -5,251 -181y = y =

Solve the linear system of equations. -59x - 2y 2х — Зу %3D-89 1 Step 1 of 3 Determine the appropriate constant to multiply by. Your goal is to solve the system using the elimination method. The coefficients of x have opposite signs. The least common multiple, or LCM, of the coefficients, 2 and -59, is 118. Multiply each equation by the number that will make the coefficients -118 and 118. -59x – 2y = 2х — Зу %3 —89 1 2(-59x – 2y) = (No Response) 2 (1) 59(2x – 3y) = (No Response) 59 (-89) -118x – |(No Response) y = 2 118x – (No Response) 177 y = -5,251 Step 2 of 3 The system from Step 1 has a variable with opposite coefficients. Add the equations and solve for the other variable. Add the equations to eliminate x. Then use the division property of equality to solve for y. -118x 4y = 2 118x - 177y = -5,251 -181y = y =

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Solve the linear system of equations. -59x 2y = 1 2х — Зу -89 Step 1 of 3 Determine the appropriate constant to multiply by. Your goal is to solve the system using the elimination method. The coefficients of x have opposite signs. The least common multiple, or LCM, of the coefficients, 2 and -59, is 118. Multiply each equation by the number that will make the coefficients -118 and 118. - 2y Зу -59x 1 2x -89 2(-59х — 2y) (No Response) 2 (1) %D 59(2x – 3y) = (No Response) 59 (-89) -118x |(No Response) 4| y = 2 118x - (No Response) 177 y = -5,251 Step 2 of 3 The system from Step 1 has a variable with opposite coefficients. Add the equations and solve for the other variable. Add the equations to eliminate x. Then use the division property of equality to solve for y. -118x 4y 118x 177y -5,251 %D -181y y =
Transcribed Image Text:Solve the linear system of equations. -59x 2y = 1 2х — Зу -89 Step 1 of 3 Determine the appropriate constant to multiply by. Your goal is to solve the system using the elimination method. The coefficients of x have opposite signs. The least common multiple, or LCM, of the coefficients, 2 and -59, is 118. Multiply each equation by the number that will make the coefficients -118 and 118. - 2y Зу -59x 1 2x -89 2(-59х — 2y) (No Response) 2 (1) %D 59(2x – 3y) = (No Response) 59 (-89) -118x |(No Response) 4| y = 2 118x - (No Response) 177 y = -5,251 Step 2 of 3 The system from Step 1 has a variable with opposite coefficients. Add the equations and solve for the other variable. Add the equations to eliminate x. Then use the division property of equality to solve for y. -118x 4y 118x 177y -5,251 %D -181y y =
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