Solve the linear programming problem. Maximize P = 40x + 50y Subject to 2x+ys 14 x+y ≤ 9 x + 2y ≤ 16 x, y ≥ 0
Solve the linear programming problem. Maximize P = 40x + 50y Subject to 2x+ys 14 x+y ≤ 9 x + 2y ≤ 16 x, y ≥ 0
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question

Transcribed Image Text:### Linear Programming Problem
---
**Objective:**
Maximize \( P = 40x + 50y \)
**Constraints:**
1. \( 2x + y \leq 14 \)
2. \( x + y \leq 9 \)
3. \( x + 2y \leq 16 \)
4. \( x, y \geq 0 \)
---
### Explanation of Constraints:
1. The first constraint \( 2x + y \leq 14 \) indicates that the sum of twice the value of \( x \) and the value of \( y \) must be at most 14.
2. The second constraint \( x + y \leq 9 \) indicates that the sum of \( x \) and \( y \) cannot exceed 9.
3. The third constraint \( x + 2y \leq 16 \) indicates that the sum of \( x \) and twice the value of \( y \) must be at most 16.
4. The fourth constraint \( x, y \geq 0 \) signifies that both \( x \) and \( y \) must be non-negative; they cannot be less than zero.
### Graphical Interpretation (for Explanation):
To solve this problem graphically:
1. **Plot each constraint on a graph:**
- \( 2x + y = 14 \)
- \( x + y = 9 \)
- \( x + 2y = 16 \)
2. **Identify the feasible region**:
- This is the region where all the constraints overlap and \( x \) and \( y \) are non-negative.
3. **Find the corner points (vertices) of the feasible region**.
4. **Evaluate the objective function \( P = 40x + 50y \) at each corner point** to find which provides the maximum value.
The graphical method provides a visual understanding, which can be supplemented with algebraic methods like the Simplex method for more complex or higher-dimensional problems.
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