Solve the linear programming problem by the simplex (y2 - 2x + 41method. Minimize 10x + 4y subject to the constraintsshown on the right.ys -x+36ys-**14yz-x+6x20, y20The minimum value of 10x + 4y is which is attained for x =(Type integers or fractions.)O and y = D.

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Description: Solve the linear programming problem by the simplex (y2 - 2x + 41method. Minimize 10x + 4y subject to the constraintsshown on the right.ys -x+36ys-**14yz-x+6x20, y20The minimum value of 10x + 4y is which is attained for x =(Type integers or fraction

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Solve the linear programming problem by the simplex (y2 - 2x + 41 method. Minimize 10x + 4y subject to the constraints shown on the right. ys -x+36 ys-**14 yz-*+6 x20, y20 The minimum value of 10x + 4y is (Type integers or fractions.) which is attained for x= and y =

Solve the linear programming problem by the simplex (y2 - 2x + 41 method. Minimize 10x + 4y subject to the constraints shown on the right. ys -x+36 ys-**14 yz-*+6 x20, y20 The minimum value of 10x + 4y is (Type integers or fractions.) which is attained for x= and y =

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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In solving maximization problem using simplex method, the optimum column is obtained by getting the column with A. smallest positive value in the Cj - Zj row variables. B. the largest positive value in the Cj - Zj row. C. zero value in the Cj - Zj row. D. the largest negative value in the Cj - Zj row.
Please answer last 3 parts
M3
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Q6: Create a model using an Algebraic Constraint block to find a solution for the non-linear equation: F(x) = 3x-2x + 6x – 8
Find the optimal solution by simplex method 3 X, - 150x, + 1 Max Z X; - 6X4 50 s/t 25x, - 600x, – 4x, + 900x, s 0 25x, - 4500x, - Xz + 150x4 3 0 Xz 3 1 uhere x;¿ O
using linear progamming simplex method solve this question. maridadi furnitures ltd is planning to make tables and chairs. they both require material and labor time. to manufacture a table and a chair requires 3 units and 4 units of direct material respectively, of which they are 96 units available in a week. marking a table or a chair each takes 6 hours and there are 168 labor hours available in a week. whereas the market for tables in unlimited, only 18 chairs can be sold weekly. the price per table and chairs are $50 ad $60 respectively whereas their unit variable costs are $38 and $40 respectively. fixed costs average $200 per week. advise maridadi ltd on the weekly production schedule in order to maximize contribution to profit.