Solve the linear programming problem by the method of corners.MinimizeC = 3x + 4y subject to 4x + y ≥42 2x + y ≥30 x + 3y ≥30 x ≥ 0, y ≥ 0 The minimum is C = at (x, y) = .

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Answered: Solve the linear programming problem by…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Use the method of corners to solve the linear programming problem. Find the maximum and minimum of Q = 5x + 7y subject to х+ 4 -X + 6. х+ Зу < 30 9. x2 0, у2 0. The minimum is P = at (x, y) = The maximum is P = at (x, у) 3
Let f(x.y) be a two variable function with fx = y and fy =x. What are the extreme points of f with constraint 4x2 + y² = 8? O a. (1,-2), (-1,-2), (-2, 2), (-1,-1) O b.(1,-2). (1,2). (-1, 2). (-1,-2) O C. (1,2), (1, -2). (2,1), (2,-1) O d. (1,1), (1,-1), (2,2), (2.-2)
I am learning about this for the first time and I did this question but feel like I did not answer the parts correctly. Please could I see how an expert would answer the whole problem to compare. the question is to construct an LP model where all the variables constrained are positive.
Can you help solve this problem with general linear programming and no technology?
Find X₁ and X₂ that maximize the objective function Z = 3x₁ + 5×₂2 with the constraint function 2x, 8 3X₁ ≤ 15 6X₁ + 5X₂ > 30 = Using the simplex method.

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Minimize	C = 3x + 4y
subject to	4x	+	y	≥	42
	2x	+	y	≥	30
	x	+	3y	≥	30
	x ≥ 0, y ≥ 0

Solve the linear programming problem by the method of corners. Minimize C = 3x + 4y subject to 4x + y ≥ 42 2x + y ≥ 30 x + 3y ≥ 30 x ≥ 0, y ≥ 0 The minimum is C = at (x, y) =