Solve the initial value problem. X - [3 -1³]X, X (0) - [!] XI= = 5 = e2t 9 cos(8t) - 9 sin(8t)] cos(8t) + sin(8t) x (t) = x (1) - ez [cos (8t) 8 sin(8t)] = e2t 5 cos(8t) [9 cos(8t) - 7 sin(8t)] [5 cos(8t) + 5 sin(8t)] x (t) = [1/0 X
Solve the initial value problem. X - [3 -1³]X, X (0) - [!] XI= = 5 = e2t 9 cos(8t) - 9 sin(8t)] cos(8t) + sin(8t) x (t) = x (1) - ez [cos (8t) 8 sin(8t)] = e2t 5 cos(8t) [9 cos(8t) - 7 sin(8t)] [5 cos(8t) + 5 sin(8t)] x (t) = [1/0 X
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Solve the initial value problem.
X - [3 -1³] x. x(0) = [1]
XI=
X,
5
x(t) = ²
X
e²t
[9058
[9 cos(8t) - 9 sin (8t)
cos(8t) + sin(8t)
x (t) = e²¹ [cos(
e2t
x (t) =
[cos(8t) 8 sin(8t)
5 cos(8t)
sin(8t)]
[9 cos(8t) - 7 sin(8t)]
[5 cos(8t) + 5 sin(8t)]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F11e04b6e-64f8-4aa9-ac1f-677dd20d1d51%2Fe1f31d30-d289-4dea-b9e9-60d02b2437d5%2Flxdyvli_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Solve the initial value problem.
X - [3 -1³] x. x(0) = [1]
XI=
X,
5
x(t) = ²
X
e²t
[9058
[9 cos(8t) - 9 sin (8t)
cos(8t) + sin(8t)
x (t) = e²¹ [cos(
e2t
x (t) =
[cos(8t) 8 sin(8t)
5 cos(8t)
sin(8t)]
[9 cos(8t) - 7 sin(8t)]
[5 cos(8t) + 5 sin(8t)]
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