Solve the initial value problem y' = (x + y − 3)² with y(0) = 0. To solve this, we should use the substitution u = x+y 3 help (formulas) u' = 1+y' help (formulas) Enter derivatives using prime notation (e.g., you would enter y' for dy). After the substitution above, we obtain the following differential equation in x, u, u'. u'=1+u help (equations) The solution to the original initial value problem is described by the following equation in x, y. help (equations) Book: Section 1.5 of Notes on Diffy Qs

Q: Is y'' = sin x a linear differential equation?

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Q: Determine the solution explicitly of the following differential equation x(y^2) y' -(y^3) =1

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Q: solve the differential equation x2yy'=(y2-1)3/2

A: To solve the given differential equation :-

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