Solve the initial value problem y' = (x + y − 3)² with y(0) = 0. - To solve this, we should use the substitution и - u' = x+y 3 help (formulas) 1+y help (formulas) dy Enter derivatives using prime notation (e.g., you would enter y' for dx After the substitution above, we obtain the following differential equation in x, u, u'. 2 u'=1+u² help (equations) The solution to the original initial value problem is described by the following equation in x, y. help (equations) Book: Section 1.5 of Notes on Diffy Qs
Solve the initial value problem y' = (x + y − 3)² with y(0) = 0. - To solve this, we should use the substitution и - u' = x+y 3 help (formulas) 1+y help (formulas) dy Enter derivatives using prime notation (e.g., you would enter y' for dx After the substitution above, we obtain the following differential equation in x, u, u'. 2 u'=1+u² help (equations) The solution to the original initial value problem is described by the following equation in x, y. help (equations) Book: Section 1.5 of Notes on Diffy Qs
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Solve the initial value problem y' = (x + y − 3)² with y(0) = 0.
-
To solve this, we should use the substitution
и
-
u' =
x+y 3 help (formulas)
1+y help (formulas)
dy
Enter derivatives using prime notation (e.g., you would enter y' for
dx
After the substitution above, we obtain the following differential equation in x, u, u'.
2
u'=1+u² help (equations)
The solution to the original initial value problem is described by the following equation in x, y.
help (equations)
Book: Section 1.5 of Notes on Diffy Qs
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