Solve the initial value problem y = (x + y – 1)² with y(0) = 0. To solve this, we should use the substitution и 3D х+у-1 help (formulas) u' 1+y' help (formulas) || dy Enter derivatives using prime notation (e.g., you would enter y for dx After the substitution above, we obtain the following differential equation in x, u, u'. help (equations) The solution to the original initial value problem is described by the following equation in x, ) help (equations)

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