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Solve the initial value problem O y(t) = cost + sint Oy(t) = Oy(t) = O y(t) = O y(t) = Oy(t) = c₁cost + c₂sint 10cost - 20sint √3cost + 10√3sint 20cost + 10sint et - e-t y" + y = 0, y() = 10, y'(π/3) = − 20 O y(t) = √3cost + √3sint O y(t) = √3cost + (√3+ 10) sint ○ y(t) = (5 + 10√3) cost + (5√√3-10) sint

Solve the initial value problem O y(t) = cost + sint Oy(t) = Oy(t) = O y(t) = O y(t) = Oy(t) = c₁cost + c₂sint 10cost - 20sint √3cost + 10√3sint 20cost + 10sint et - e-t y" + y = 0, y() = 10, y'(π/3) = − 20 O y(t) = √3cost + √3sint O y(t) = √3cost + (√3+ 10) sint ○ y(t) = (5 + 10√3) cost + (5√√3-10) sint

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve the initial value problem Oy(t) = cost + sint y(t) = y(t) = O y(t) = O y(t) = O y(t) = O O c₁cost + c₂sint 10cost 20sint ○ y(t) = √3cost + 10√3sint -20cost + 10sint e¹ - e-t y(t) = √3cost + √3sint y(t) = √3cost + (√3+ 10) sint y″ + y = 0, y( ²3 ) = (5 + 10√3) cost + (5√√/3 - 10) sint = 10, y'(π/3) = - 20
Transcribed Image Text:Solve the initial value problem Oy(t) = cost + sint y(t) = y(t) = O y(t) = O y(t) = O y(t) = O O c₁cost + c₂sint 10cost 20sint ○ y(t) = √3cost + 10√3sint -20cost + 10sint e¹ - e-t y(t) = √3cost + √3sint y(t) = √3cost + (√3+ 10) sint y″ + y = 0, y( ²3 ) = (5 + 10√3) cost + (5√√/3 - 10) sint = 10, y'(π/3) = - 20
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