Solve the initial value problem f'(x) = cos x + sec² x, Π ƒ ( 7 ) = √2 2 No correct answer Of(x) sin x tan x + 1 Of(x) = sin x + tan x + C ○ f(x) = sin x + tan x - 1 x 49 to x = 53. Use a differential to Let y = √ and suppose x increases from x = approximate how y changes in response. Recall that dy = y'dx. y increases by about 27 y increases by about 4/5 4 y decreases by about 7 2 y decreases by about

Q: If f(x) =sin x sin2x sin3x find f" (x)

A: Given f(x) and find second derivative of this function. We use trigonometry relations and derivative…

Q: Find the value →21. csc (sec- 2) + cos (tan¬1 (– V3))

A:

Q: If f(x) = tan (3x), then f'(x) = (A) 12 tan (3x) sec?(3x) (B) 4 tan (3æ) sec2(3x) (C) 12 tan (3x)…

A: derivative

Q: find the slope Of the followiny functions at the gruen point: at Xo to JL

A:

Q: If f(x) = cos(x) +3z³, what is f'(æ)? O f'(x) = sin(x) +3z³ O f'(x) = sin(x)+ 9x² O f'(x) =…

A:

Q: Q2/ Find f (x) : 1- f(x) = 4 cos x + 2 sin x 2- f(x) = cos x - x csc x 3- f(x) %3D %3D cot x 1+cscx…

A: As per guidelines we can solve only one question at a time. So the first question can be solved as…

Q: tan x/4 + V3 = 0 Solve graphically in [-27, 2n] %3D

A: We have given that, tanx4+3=0;   -2π≤x≤2π Let us consider that, y=tanx4            ⋯⋯1y=-3…

Q: Given f''(x) = = Find 76 10 - - 36 sin(6x) and f'(0) = 2 and ƒ(0) = − 6.

A:

Q: Differentiate each function a) f(x) =sin'[ (tan (cos (x²)) ] b) g(x) =/ sec(x* +2x) c) h(x)=V5 +3x²…

A: As per our guidelines we need to solve only 3 subparts.please repost the remaining subparts as other…

Q: 3 a Differentiate b Differentiate sin x and hence find an anti-derivative of COS X cos(2x) sin(2x) 1…

A:

Q: Find f'(x) if f (x) = 2 cos x + 3 sin x. f'(x) =

A:

Q: 10x 19) y Sin'(5x') (ans.: JI-25 x' 20) y= Cot ) (ans.: 1+ x' 6x' 21) y=tan'V4x'- 2 (ans.: (4x'-1…

A: As per guidelines we can only solve first question or first three subparts of the question, I am…

Q: Verify the equation

A: To establish the given trigonometric identity

Q: Let ƒ(x) = (cos( − 4x – 5)) (sin(6x − 2)). Then ƒ'(x) =

A: f(x)=(cos(-4x-5))(sin(6x-2))

Q: If f(x) f'(x) = f'(4) = = 4 sin x 3 + cos x " then

A:

Q: cos(4x) cos(2x) sin(4x) sec(2x) 12. Verify: - sin(2x)

A: cos(2x ) =cos2(x)-sin2(x) = 2cos2(x)-1 =1-2sin2(x) sin(2x) = 2sin(x) cos(x)

Q: Show that the function f(x)=x^-4 +cos(-2x) is even, odd, or neither."

A: Given, f(x)= x^-4 +cos(-2x) f(x)= (1/x)4 + cos(-2x)

Q: Find f'(x) if f (x) = 3 cos x + 8 sin x. f'(x) =

A: We need to differentiate the given Function.

Q: If f(x) = f'(x) = f'(1) = 5 sin x 3+ cos x then

A:

Q: Determine f(x) a. f(x) = 4 sin² (x - 2) b. f(x) = 2(cos x)(sec² x)

A: (a) The given function is f(x)=4sin2x-2 Find the first derivative…

Q: Find f'(x) if f(x) = tan-1 2x sec²(x) 1 1+x² 2x 1+x² 2x 1+x¹ 2x 1+x² 1-¹ (x²).

A:

Q: If f (x) = - cos(x), then f (10) (x) is equal to (A) - sin (x) ® -cos(x) © sin(x) D cos(x)

A:

Q: If f(x) ƒ'(x) = f'(2) = 4 sin x 3 + cos x then

A: derivative

Q: 9) Find f(x) if f'(x) = 7 sin x + 2x - 3 and f(0) = -3

A: Obtain f(x) by integrating the given first derivative as follows.

Q: O find fx) if CoSx @ £(x)=. Sin X O flx) = x-4CSC x+2 Cot X © f(x)= (x).cotx 3- COSX. CSCX

A: SOLUTION-