x²-7x+10<0 (x-5)(x-2)<0 X= 5 X=2 8 Test points -3 6 (x-5) Inequalities x²-2570 (x15)(xJ -" Jest points-7 (x+5) (x-5) + + Conclusion t + (-5) (5, 6) (x-2) Conclusion - + + - (2,5) * Solve the inequality. (3x-5)(2x+5)≤0 The solution set is (Simplify your answer. Use integers or fractions for any numbers in the expression. Type your answer in interval notation.) Sketch the graph of the quadratic function. Give the vertex and axis of symmetry.

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