Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter5: Linear Inequalities
Section: Chapter Questions
Problem 6SGR
Related questions
Question
Please see attachment for math question.
![### Solving Linear Inequalities
The problem presented is to solve the following inequality:
\[
-13 + 8x \leq 12 + 9x
\]
**Steps to Solve the Inequality:**
1. **Simplify the Inequality:**
Move all terms involving \(x\) to one side and constants to the other side.
\[
-13 + 8x - 9x \leq 12
\]
Simplify the \(x\) terms:
\[
-13 - x \leq 12
\]
2. **Isolate \(x\):**
Add 13 to both sides to isolate the \(x\) term.
\[
-x \leq 25
\]
3. **Solve for \(x\):**
Multiply both sides by -1, remembering to reverse the inequality sign:
\[
x \geq -25
\]
The solution to the inequality is:
\[
x \geq -25
\]
**Expressing the Solution as an Interval:**
Enter your answer as an interval. Use "oo" (two lower case "o"s) to represent an infinity sign.
The solution in interval notation is:
\[
[-25, \infty)
\]
**Input the Solution:**
Enter your answer in the following format:
\[
[-25, \infty)
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4ed3be98-469b-4630-9026-6d8c89f34a56%2F2ed2b5e1-a7b9-4e42-b8cf-244dca017704%2Fqv12okr_processed.png&w=3840&q=75)
Transcribed Image Text:### Solving Linear Inequalities
The problem presented is to solve the following inequality:
\[
-13 + 8x \leq 12 + 9x
\]
**Steps to Solve the Inequality:**
1. **Simplify the Inequality:**
Move all terms involving \(x\) to one side and constants to the other side.
\[
-13 + 8x - 9x \leq 12
\]
Simplify the \(x\) terms:
\[
-13 - x \leq 12
\]
2. **Isolate \(x\):**
Add 13 to both sides to isolate the \(x\) term.
\[
-x \leq 25
\]
3. **Solve for \(x\):**
Multiply both sides by -1, remembering to reverse the inequality sign:
\[
x \geq -25
\]
The solution to the inequality is:
\[
x \geq -25
\]
**Expressing the Solution as an Interval:**
Enter your answer as an interval. Use "oo" (two lower case "o"s) to represent an infinity sign.
The solution in interval notation is:
\[
[-25, \infty)
\]
**Input the Solution:**
Enter your answer in the following format:
\[
[-25, \infty)
\]
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