Solve the indicated problem 43.1ML of o.68M is required to hydroxide , hydrochloric acid. wha t is the strontium neutralise M 74.OML de composchón of the aced ? bowallo T14.6mL of 0.23M calcium hudro xide is reguired to neutra lise 65.o mL of acetic a cid. what is the Concentration of the acid? hydrobromic acid is required to neutralize 75.oml of a 30lution of barium hydro xide. what is the © 52:3m2 of 8.26M Concentra hon of the acid ? toNt sbiro

Q: what volume (L) of 0.404 M potassium hydroxide solution would just neutralize 60.6 mL of 0.388…

A:

Q: What volume (in mL) of 0.2900 M HCl is required to neutralize 50.00mL of 0.8000M NaOH?

A: Given -> Molarity of HCl = 0.2900 M = M1 Molarity of NaOH = 0.8000M = M2 Volume of NaOH = 50.00…

Q: 25.0mL of 0.212 M NaOH is neutralized by 13.6 mL of an HCL solution.  The molarity  of the HCL…

A: At equivalence point (neutralisation point), number of moles of NaOH is equal to number of moles of…

Q: How many mililiters of 0.250 M NaOH are required to neutralize 30.4 mL of 0.146 M HCI?

A: Molarity of NaOH(M1) = 0.250 MVolume of NaOH(V1) = ?Molarity of HCl(M2) = 0.146 MVolume of HCl(V2)…

Q: How many milliliters of 0.100 M HClO₃ are required to neutralize 40.0 mL of 0.140 M KOH?

A: The objective of this question is to find out the volume of 0.100 M HClO3 required to neutralize…

Q: A 0.8159 sample of HCl was placed into a 50mL volumetric flask and the sample was thoroughly…

A: In the titration process of an acid and a base which are in a ratio of 1:1, the below given equation…

Q: What volume (mL) of 3.50 x 10--1 M hydrochloric acid can be neutralized with 305mL of 0.600 M sodium…

A: The given reaction is a neutralization reaction between NaOH and HCl. Concentration of HCl = Volume…

Q: What volume (in mL) of 0.2800 M HCl is required to neutralize 75.00mL of 0.6000 M LiOH?

A: Answer: This question is based on stoichiometric calculation where moles of LiOH needs be converted…

Q: f 50.0 mL of concentrated (18M) sulfuric acid is diluted to a total of 1.0 L, what is the new…

A: Given, Initial concentration (M1) = 18 M. Initial volume (V1) = 50.0 mL = 0.05 L Final volume (V2) =…

Q: How many mL of B.3M HCl would Ineed to prepare 500ML of 2i oM Hec1?

A: M1V1 = M2V2 M1 is molarity of concentrated HCl V1 is the volume of concentrated HCl M2 is the…

Q: i volume (in mL) of 0.250 M HCI would be required to completely with 4.0 0 a of ALin the following…

A: The number of moles of aluminium can be calculated as, Now, as per the balanced chemical reaction,…

Q: 4. Find the concentration of a potassium hydroxide solution if 23 mL were used to neutralize 14 ml…

A: GIven : The concentration of hydrobromic acid (HBr)=2.3 M or 2.3 mol/L The volume of solution used…

Q: 1. How many grams of benzoic acid (C,H.COOH) are contained in a 75 ml solution at 0.21 M…

A:

Q: A 35.0 mL solution of Sr(OH), is neutralized with 20.5 mL of 0.200 M HNO3. What is the concentration…

A: The objective of this question is to find the concentration of the original Sr(OH)2 solution. To do…

Q: What volume of 0.195 M KOH,?, can be neutralized with 57.0 mL of 1.15 M HNO3? (in mL)

A: Here given, Strength of KOH (S1) = 0.195 M Volume of KOH (V1) =? Strength of HNO3 (S2) = 1.15 M…

Q: What volume in milliliters of 0.250 M HNO2 is required to neutralize 36.0 milliliters of a 0.150 M…

A: Balanced chemical equation HNO2   +   NaOH → NaNO2 + H2O

Q: a) How many milliliters of0.150M HES04 are required to give 0.184 g of sulfuric acid? b) Determine…

A:

Q: art I: Multiple Choice 1. How many grams of Sr(OH), are contained in 1200 mL of 0.0350 M Ca(OH),…

A: Given that the volume of solution is Convert to liters.

Q: How many ml of 0.385 M perchloric acid solution is required to react with 3.75g of chromium metal

A: Molarity of perchloric acid = 0.385 MMass of Cr = 3.75 g

Q: How many milliliters of water must be added to 103 mL of 1.50 M HCI to give 1.00 M HCI? (Assume the…

A: • The values provided in the question are:-  i) Initial concentration of HCl solution, M1 = 1.50 M…

Q: 0.340 M AI(NO.),. Express your answer with therppropriate unlts. View Avallable Hint(s) empyteymbole…

A: Molarity is the number of moles of solute dissolve in ine litre of the solution.

Q: Solid calcium bromide is slowly added to 125 mL of a 0.415 M sodium sulfite solution until the…

A: Answer: When the ionic product of a sparingly soluble salt becomes greater than its solubility…

Q: What volume in milliliters of 0.100 M HCIO3, is required to neutralize 40.0 mL of 0.205 M KOH?

A:

Q: What volume of 0.100 M sulfuric acid could be neutralized by 40.00 ml of 0.100 M potassium hydroxide…

A: Normality = Molarity x n  Where n is the basicity or valence factor N1V1 = N2V2  Basicity of acid is…

Q: Solid potassium bromide is slowly added to 125 mL of a 0.304 M silver acetate solution until the…

A: Solution                         Given that Bromide = 0.0377M Volume = 125ml Silver acetate =…

Q: )A 25.0 mL Jamole d an acetic acid stto Cha= 1.76x 105) is ttrated ith ď 0.175 M NaoH Siti. Siti.…

A: It is given that 25mL of acetic acid is titrated with 0.175 M of sodium hydroxide solution and the…

Q: 21. In which of the following solutions will the reaction with 1.0 g C'aCO, he fastest? 100 cm' of…

A: According to Le-chatellier's principle,  if product is removed from the reaction medium ,then more…

Q: An aqueous solution of hydroiodic acid is standardized by titration with a 0.160 M solution of…

A: Neutralization :-  The reaction of an acid with a base to form salt and water is kbown as…

Q: What volume of 0.188 M KOH, V, can be neutralized with 65.5 mL of 1.40 M HNO,? mL V =

A: Question Belong to acid base reaction. Here strong acid will react with strong base to produce salt…

Q: A titration flask contains 0.00425 moles of an acetic acid sample a. Determine the moles of the base…

A: Given-> Moles of acetic acid = 0.00425 mole Molarity of base = 0.200 M

Q: How many millilitres of 0.157M nitric acid are rrequired to neurtralize 22.1ml of 0.194 M sodium…

A: Given :  Molarity of nitric acid solution = 0.157 M  Molarity of sodium hydroxide solution = 0.194 M…

Q: What volume, in milliliters, of a 0.175 M HCI solution is needed to neutralize 8.75 mL of 0.500 M…

A:

Group 15 elements

The elements of group 15 are phosphorus, nitrogen, bismuth antimony, and arsenic. The most abundant element which is present in the air is nitrogen and the percentage of nitrogen present in the air is 78%. In the free state, the elemental nitrogen is present as diatomic gas (N2). In the organic matter obtained from plants and animals, phosphorus is the dominant element present. In nucleic acids, phosphate groups are present. Phosphates are also found in teeth and bones. The other elements arsenic, bismuth, and antimony are found as sulfides. Arsenopyrite, bismuth glance, and stibnite are examples of sulfides of arsenic, bismuth, and antimony respectively.